Given:
The line passing through (-2,5) and (2,p) has a gradient of .
To find:
The value of p.
Solution:
If a line passes through two points, then the slope of the line is:
The line passing through (-2,5) and (2,p). So, the slope of the line is:
It is given that the gradient or slope of the line is .
On cross multiplication, we get
Divide both sides by 2.
Therefore, the value of p is 3.
Answer:
D
Step-by-step explanation:
given ×
the 2j on the denominator of the first fraction cancels with the 2j on the numerator of the second fraction, leaving the expression in simplified form as
= → D
Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
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