Solution to equation
for all real values of x is
.
<u>Step-by-step explanation:</u>
Here we have ,
. Let's solve :
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
By quadratic formula :
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
But at
we have equation undefined as
. Hence only solution is :
⇒ 
Since , 
⇒ 
Now , General Solution is given by :
⇒ 
Therefore , Solution to equation
for all real values of x is
.
Answer: The flagpole is about 22.3 feet tall.
This is roughly the size of a two story building, assuming each floor is 10 feet or so.
Since this height is under 25 ft, this flagpole is in compliance with the regulation.
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Work Shown:
The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.
The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.
Use the tangent rule to connect the opposite and adjacent sides.
Solve for x.
tan(angle) = opposite/adjacent
tan(25) = (x-5.5)/36
36*tan(25) = x-5.5
x-5.5 = 36*tan(25)
x = 36*tan(25)+5.5
x = 22.28707569358
x = 22.3 ft is the approximate height of the flagpole
Make sure your calculator is in degree mode.
The height is not over 25 ft, so this flagpole meets the requirements.
Answer:
19 and 2
Step-by-step explanation:
Let x represent the first number and y represents second number
x + y = 19
x - y = 17 add two equations up
2x = 36 divide both sides by 2
x = 19 and since the difference is 17 the other number is 2
Answer:
it is 29in
Step-by-step explanation:
A shape that is similar to another shape will be enlarged by a scale factor.
Each corresponding sides should give the same scale factor
Side GI corresponds to side JL
Side GH corresponds to side JK
Side HI corresponds to side KL
The correspond sides whose length are given is
GH = 4 and JK = 8
Side JK is twice longer than GH
All the other sides of triangle JKL are twice longer than triangle GHI, so we want that the side JL to be twice of the sides GI
Side GI = 6
Side JL = 6 × 2 = 12
Answer: y = 12