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Aloiza [94]
3 years ago
5

The average wavelength in a series of ocean wave is 16.0m. A wave crest arrives at the shore on average every 10.0, so the frequ

ency is 0.100 Hz. What is the average speed of waves.
Mathematics
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

gay

wunuwu unwind and relax and enjoy the rest of the rest of the rest

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A grocery bag contains x apples, each weighing of a pound, and y pounds of grapes. The total weight of the grocery bag is less t
kupik [55]
First let's write out the inequality before choosing a graph.

x apples each weighing 1/3 of a pound: 1/3x

y pounds of grapes: y

So...

1/3x + y < 5

The maximum weight is 4 pounds since the total weight of both the grapes and apples are less than 5.

In the y-axis, the first, third, and fourth graphs already exceed the capacity of 5 pounds.

So, by process of elimination, the correct graph for this problem is the second one.
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In a dog show , there will be a gold and a silver medal awarded. There are 5 finalist. In how many different ways can the 2 meda
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in 20 ways you can give medals

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What is the sum of (3x-2)(2x-7)​
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Each day, Robin commutes to work by bike with probability 0.4 and by walking with probability 0.6. When biking to work injuries
kvasek [131]

Answer:

64.65% probability of at least one injury commuting to work in the next 20 years

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}&#10;

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Each day:

Bikes to work with probability 0.4.

If he bikes to work, 0.1 injuries per year.

Walks to work with probability 0.6.

If he walks to work, 0.02 injuries per year.

20 years.

So

\mu = 20*(0.4*0.1 + 0.6*0.02) = 1.04

Either he suffers no injuries, or he suffer at least one injury. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}&#10;

P(X = 0) = \frac{e^{-1.04}*1.04^{0}}{(0)!} = 0.3535&#10;

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3535 = 0.6465

64.65% probability of at least one injury commuting to work in the next 20 years

3 0
2 years ago
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