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alina1380 [7]
3 years ago
10

HELP PLEASE Find the equation of the line The line passes through the points (2, 3) and (-3, -2)

Mathematics
1 answer:
Vladimir79 [104]3 years ago
7 0
Y= x+1



y-3 = (-2-3)/(-3-2) (x-2)
y-3 = 1 (x-2)
y = x-2+3
y=x+1



Mark brainliest please
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The sum of the angle measures of a polygon with s sides is 2880. Find s. A. 20 B. 16 C. 17 D. 18
siniylev [52]
I think the answer is D. 18

8 0
3 years ago
Please solve this please​
12345 [234]

Answer: The measure of the supplement is 150 degrees. The other angle is 30 degrees.

Step-by-step explanation:

angle: x/5

x+x/5=180

5x+x/5=180

6x/5=180

x=180(5/6)

x=150

Other angle: 150/5=30

or 180-150=30

4 0
2 years ago
Can someone please help convert these so they have the same denominator??
ratelena [41]

The LCM of the denominators is 120. In other words, the denominators can multiply to 120.

3 * 40 = 120

40 * 2 = 80

Tigers: P = 80/120

24 * 5 = 120

24 * 4 = 96

Redbirds: P = 96/120

8 * 15 = 120

3 * 15 = 45

Bulldogs P = 45/120

60 * 2 = 120

60 * 1 = 60

Titans P = 60/120

Answer

Tigers: P = 80/120

Redbirds: P = 96/120

Bulldogs: P = 45/120

Titans: P = 60/120

5 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

5 0
3 years ago
X-3= 0 and 4x+2y-1= 0​
Assoli18 [71]
X-3=0
x=3

4x+2y-1=0
4(3)+2y-1=0
12+2y-1=0
11+2y=0
2y=-11
y=-5.5
3 0
2 years ago
Read 2 more answers
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