Let after n week both tanks have same quantity of water .
for first tank
=============
tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
==============
quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
Answer:
ibk looks it up please hope this helps
Answer:
A) 159.135 = X
B) 2,531.25 = X
C) 6,187.5 = X
D) 831,947.46 = X
Step-by-step explanation:
The following investments are required to be calculated:
A) $ 150 at 3% interest for 2 years
B) $ 750.00 at 1/2% interest for 3 years
C) $ 2,250.00 at 1 3/4% interest for 1 year
D) $ 2,550.00 at 3 1/4 interest for 4 years
Therefore, the following calculations must be performed:
A)
150 x (1 + 0.03) ^ 2 = X
150 x 1.03 ^ 2 = X
159.135 = X
B)
750 x (1 + 0.5) ^ 3 = X
750 x 1.5 ^ 3 = X
2,531.25 = X
C)
2,250 x (1 + 1.75) = X
2,250 x 2.75 = X
6,187.5 = X
D)
2,550 x (1 + 3.25) ^ 4 = X
2,550 x 4.25 ^ 4 = X
831,947.46 = X
Answer:
gfs
Step-by-step explanation: