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kkurt [141]
4 years ago
8

The reduced coenzymes generated by the citric acid cycle donate electrons in a series of reactions called the electron transport

chain. The energy from the electron transport chain is used for oxidative phosphorylation.
Which compounds donate electrons to the electron transport chain?
H 2 O O 2 ADP FAD FADH 2 NADH ATP NAD +
Which compound is the final electron acceptor?
ADP NADH H 2 O O 2 NAD + FADH 2 ATP FAD
Which compounds are the final products of the electron transport chain and oxidative phosphorylation?
FADH 2 ADP FAD O 2 H 2 O NADH NAD + ATP
Biology
1 answer:
natka813 [3]4 years ago
4 0

Answer:

The answer of ist question FADH2,NADH 2nd question O2  3rd question NAD+,FAD,H2O,ATP.

Explanation:

Ist answer

During electron transport chain electrons are donated by reduced coenzymes such as NADH and FADH2.

2nd answer

During electron transport chain oxygen or O2 act as terminal electron acceptor which accepts and then undergo reduction to generate H2O.

3rd answer

The final products of electron transport chain and oxidative phosphorylation are NAD+, FAD,H2O and ATP.

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agasfer [191]
 <span>I is dominant, i is recessive. The A's and B's are just show which allele I is. When there is just one dominant allele, it masks the recessive in blood typing. Remember IA and IB are codominant. 

O is always ii 
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B is IBi (heterozygous) or IBIB (homozygous) 
AB is always IAIB 

Remember: You get one allele from each parent! 

1. Father must be ii, mother must be ii, so all children must be ii. 

2. Father is IAIA (the homozygous one), the mother is IBIB, so the only possibility for the children is IAIB, because you get one allele from the father and one from the mother. 

3. Father is IAi, mother is IBi, so the children can be any of the blood types, because they can have all the combinations of genotypes. 

4. Father is ii, mother is IAIB. Children can only be IAi or IBi. 

5. Father is IAIB, mother is IAIB. Children can be IAIA, IBIB, or IAIB. 

Example of Punnett square: 
3. Father is type A, heterozygous, mother is type B, heterozygous 
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_______IA ____ i 

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Sorry, that was difficult on here, hope it's understandable. 
The father's alleles run across the top, the mother's are on the side, you follow to where they meet to find the possibilities for the children. IBIA (AB blood type), IBi (B), IAi (A), and ii (O) are the possibilities in this case. 

Hope that helps!</span>
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