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vampirchik [111]
3 years ago
9

Select the correct answer. This graph represents a quadratic function. What is the value of a in this function’s equation? A)-1

B)2 C)1 D)-2

Mathematics
2 answers:
Alchen [17]3 years ago
8 0

Answer:

-2

Step-by-step explanation:

Schach [20]3 years ago
5 0

Answer:

Step-by-step explanation:

We will use the work form of a quadratic to determine what a is...in fact we will write the equation for the whole thing in the process, because it's part of solving for a.

y = ±|a|(x - h)² + k

where x and y are from a coordinate point on the graph, h and k are the coordinates of the vertex, the absolute value of a indicates how steep or flat the graph is compared to the parent graph, and the ± is because a positive parabola opens up and a negative one opens upside down.

The vertex is (0, 9) and the coordinate point I chose to use is (3, 0). Filling those in and solving for a:

0 = ±|a|(3 - 0)² + 9 and

0 = ±|a|(3)² + 9 and

-9 = ±|a|9 and

-1 = ±|a| so a = 1. Because this is an upside down parabola the negative is out front, but a is independent of it. The correct choice is C. The quadratic function is

y=-x^2+9 or in more detailed form:

y=-(x-0)^2+9

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If Sarah is 24 years younger than her mother and if the sum of their ages is 68, how old is Sarah?
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Which is part of the process in the formation of hail pellets? They are tossed up and down in clouds. They lose layers of ice an
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2 years ago
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
HELP PLEASE WILL GIVE BRAINLIEST WORTH 50 POINTS
Alja [10]

Answer:

y = 8.13 x -16125.713


hope it helps

Step-by-step explanation:

Sum of X = 14004

Sum of Y = 977

Mean X = 2000.5714

Mean Y = 139.5714

Sum of squares (SSX) = 53.7143

Sum of products (SP) = 436.7143

Regression Equation = ŷ = bX + a

b = SP/SSX = 436.71/53.71 = 8.13032

a = MY - bMX = 139.57 - (8.13*2000.57) = -16125.71277

ŷ = 8.13032X - 16125.71277

8 0
3 years ago
Read 2 more answers
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