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vampirchik [111]
3 years ago
9

Select the correct answer. This graph represents a quadratic function. What is the value of a in this function’s equation? A)-1

B)2 C)1 D)-2

Mathematics
2 answers:
Alchen [17]3 years ago
8 0

Answer:

-2

Step-by-step explanation:

Schach [20]3 years ago
5 0

Answer:

Step-by-step explanation:

We will use the work form of a quadratic to determine what a is...in fact we will write the equation for the whole thing in the process, because it's part of solving for a.

y = ±|a|(x - h)² + k

where x and y are from a coordinate point on the graph, h and k are the coordinates of the vertex, the absolute value of a indicates how steep or flat the graph is compared to the parent graph, and the ± is because a positive parabola opens up and a negative one opens upside down.

The vertex is (0, 9) and the coordinate point I chose to use is (3, 0). Filling those in and solving for a:

0 = ±|a|(3 - 0)² + 9 and

0 = ±|a|(3)² + 9 and

-9 = ±|a|9 and

-1 = ±|a| so a = 1. Because this is an upside down parabola the negative is out front, but a is independent of it. The correct choice is C. The quadratic function is

y=-x^2+9 or in more detailed form:

y=-(x-0)^2+9

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Translate each of these statements into logical expressions by using quatifiers and predicates with one or two variables. (a) A
nikdorinn [45]

Answer:

a) A = \{\exists x \in M, \exist y \in U\,|\,xGy \}, b) B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}, c) C = \{\forall x \in M\,|\,xI \}, d) D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \} , e) E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}

Step-by-step explanation:

a) x - A student, M - Set of students of discrete math class, G - has lived in, y - Florida, U - Set of states of the United States of America.

A = \{\exists x \in M, \exist y \in U\,|\,xGy \}

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B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}

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C = \{\forall x \in M\,|\,xI \}

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D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \}

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E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}

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3 years ago
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