Hello,
Remenber:
if S=(0,0) y²=2px then F=(p/2,0 and d:x=-p/2
Let's pose
x'=x-3
y'=y-1 axes passing by the point (3,0) in base (x,y) and (0,0) in base (x',y')
y'²=2p'x'
d': x'=-5=-p'/2 ==> p'=10 and y²=20x'
Returning in base (x,y) : (y-1)²=20(x-3)
Answer B
In intercept form, the plane that has these intercepts is ...
... x/(x-intercept) + y/(y-intercept) + z/(z-intercept) = 1
... x/1 + y/(-1) + z/2 = 1
... 2x -2y +z = 2 . . . . . in standard form
Answer:
it would be 5 because there's 4 x's on 2 and there's 1 on 0
6x + 1 - (2x - 5) =
6x + 1 - 2x + 5 =
4x + 6 <==
Answer:
0 | -6
____
3 | -15
Step-by-step explanation:
just plug in the numbers they give u in the chart
when x = 0 -> y = -3*0-6 = -6
when y = -15 -> -15 = -3x-6 -> x = 3