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Setler79 [48]
3 years ago
6

Select all of the ratios that are equivalent to 4 to 7

Mathematics
1 answer:
NARA [144]3 years ago
6 0

Answer:

4/7= 12/21- mutiply the fraction by 3

(4)(3)/(7/(3)= 12/21

4/7= 16/28 - mutiply by 4

4/7= 20/35- mutiply by 5

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How do I solve <br><img src="https://tex.z-dn.net/?f=%20%20%5Csin%28%20a%20%29%20%20%3D%20.8325" id="TexFormula1" title=" \sin(
Serga [27]

Answer:

a=56.4\degree

Step-by-step explanation:

Let a be an acute angle.

To solve: \sin(a)=0.8325, we take the sine inverse of both sides to obtain:

\sin^{-1}(\sin(a))=\sin^{-1}(0.8325)

Recall  composition property of a function and its inverse function.

f^{-1}(f(x))=x

We apply this property to the left hand side to obtain;

a=\sin^{-1}(0.8325)

We now use our scientific calculator to obtain;

a=56.3564115\degree

We round to the nearest tenth to obtain;

a=56.4\degree

4 0
3 years ago
Please answer
beks73 [17]

Answer:

(0,8)

Step-by-step explanation:

8 0
3 years ago
86[]×[]=2325
forsale [732]

Answer:

235

Step-by-step explanation:

The square root of 55,225 is = 235

because,

235 x 235 = 55,225

8 0
3 years ago
I need help please help me​
Deffense [45]
Is there anwer choices
3 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
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