45÷10? a.45 b 45 c .045 d 4.5
2 answers:
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Using a system of equations, it is found that:
- For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
- For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
- For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.
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The variables of the system are:
- x, which is the number of $29 tickets sold.
- y, which is the number of $34 tickets sold.
Total of 8,000 seats, all can be sold, thus:
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For a profit of $255,000, we have that:
For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
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For a profit of $271,000, we have that:
For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
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For a profit of $235,000, we have that:
For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.
A similar problem is given at brainly.com/question/22826010