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Ne4ueva [31]
3 years ago
9

When solving - 1/8 (x + 35) = -7 what is the correct sequence of operations? need help asap :c

Mathematics
2 answers:
Amanda [17]3 years ago
8 0

Answer:

get stuff out of parentheses solve obvious problems, solve x

Anarel [89]3 years ago
5 0

Answer:

always follow "pemdas" parthensies, exponets, muiltiplication, divison, addition, subtraction

Step-by-step explanation:


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…. 4x+4+x-1=86 …. X=83/5
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3 years ago
Which value is included in the solution set for the inequality graphed on the number line​
marissa [1.9K]

Answer:

-5

Step-by-step explanation:

On the number line, the arrow is from -2 (opens) to the left; that means solutions will be any values less than -2

So

-5 < -2 : YES ( solutions will be any values less than -2)

-2 = -2 : NO  (solutions will be any values less than -2)

0 > -2 : NO  (solutions will be any values less than -2)

3 > -2 : NO  (solutions will be any values less than -2)

Answer

- 5

3 0
3 years ago
Read 2 more answers
The sum of two numbers is 2. The sum of three times the larger and twice the smaller is 14. Find the numbers.
anzhelika [568]

For this case we have to:

x: Be the variable that represents the largest number

y: Be the variable that represents the smallest number

We propose a system of equations:

x + y = 2\\3x + 2y = 14

From the first equation we have to:

x = 2-y

Substituting in the second equation:

3 (2-y) + 2y = 14\\6-3y + 2y = 14\\6-y = 14\\-y = 14-6\\-y = 8\\y = -8

We look for the value of "x":

x = 2 - (- 8)\\x = 2 + 8\\x = 10

Answer:x = 10\\y = -8

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4 years ago
Find the square Root of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B37%7D%20" id="TexFormula1" title=" \sqrt{37} " alt="
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Answer:

\approx \frac{73}{12}\left(1 - \frac{1} {2\cdot73^2}\right)

Step-by-step explanation:

= \sqrt{\frac{73^2-1) 1}{12^2}} \\

= \sqrt{\frac{73^2}{12^2}\cdot\frac{73^2-1}{73^2}} \\

= \sqrt{\frac{73^2}{12^2}}\sqrt{\frac{73^2-1}{73^2}}\\

=\frac{73}{12}\sqrt{1 - \frac{1}{73^2}} \\

\approx \frac{73}{12}\left(1 - \frac{1} {2\cdot73^2}\right)

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3 years ago
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astra-53 [7]
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