Answer:
Q1: 12.5
Q3: 16
IQR: 3.5
Step-by-step explanation:
Mean : 14.25
Median : 13.5
Mode : 13, 12
Range: 6
Minimum :12
Maximum: 18
Count n: 8
Sum: 114
Quartiles Quartiles:
Q1 --> 12.5
Q2 --> 13.5
Q3 --> 16
Interquartile
Range IQR: 3.5
Outliers: none
To figure out the size of a rectangle that would represent the swimming pool, you will use the formula for volume of a rectangle or prism to solve for the area of the base.
V = Bh
1200 = 5B
B = 240 square feet
To get an area of 240 ft.², you could use the dimensions 10' x 24'. Another possibility would be 8' x 30'.
Answer:
In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus three over root seven
Step-by-step explanation:
Given that sin ∅ =3/4 It means the ratio of the opposite side to the hypotenuse side is 3:4.
Using the Pythagoras theorem we can calculate the hypotenuse adjacent as follows.
a²+b²=c²
a²=c²-b²
a²=4²-3²
a²=16-9
a²=7
a=√7
Then Cos ∅= opposite/ adjacent
=√7/4
Then Tan ∅ = opposite/adjacent
=3/√7
In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus three over root seven.
Answer:
Find out the how much chlorine is in the pool .
To prove
As given
The amount of chlorine in a swimming pool varies directly with the volume of water.
The pool has 2.5 milligrams of chlorine per liter of water.
i.e
2.5 milligrams of chorine = 1 litre of water
There are 8000 gallons of water in the swimming pool.
As 1 gallons = 3.78541 litre (Approx)
Now convert 8000 gallons of water in litres.
8000 gallons = 8000 × 3.78541 litre
= 30283.28 litres
Now calculate chlorine in the pool for 30283.28 litres of waters.
As
2.5 milligrams of chlorine = 1 litre of water
2.5 × 30283.28 milligrams of chlorine = 30283.28 litre of water
75708.2 milligrams of chlorine for 30283.28 litre of water .
The answer is d as for any given length you could have any given volume by altering the cross sectional area of the pool and vice versa
