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aalyn [17]
2 years ago
10

john is running in a race. the race is 25 miles long. after two hours, john has run 7 miles. how many miles, m does john have le

ft to run?
Mathematics
1 answer:
erastovalidia [21]2 years ago
8 0
25-7=18
John has 18 miles to run left
And 300 mins to finish the race, 60×5=300
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Plz can you help me, thank you :)
Pepsi [2]

Answer:

A

c= s^3 AJ / km^2

Step-by-step explanation:

If you plug in this answer in the equation, you cancel out the km^2 and AJ, leaving s^3 = s^3

5 0
3 years ago
Write <br> 0.28<br> as a fraction in simplest form.
Usimov [2.4K]

7/25

First thing you want to do is put it over 100

28/100

Now divide by 4

28÷4=7

100÷4=25


6 0
3 years ago
Read 2 more answers
6x^2 + 3x - 1 =0 Use the Quadratic Formula to solve for X
Citrus2011 [14]
The answer is :x=3±√3312x=3±3312x≈0.72871355,−0.22871355
Use the quadratic formula to find the solutions.<span><span><span><span>−b</span>±<span>√<span><span>b2</span><span><span>−4</span><span>(<span>ac</span>)</span></span></span></span></span><span>2a</span></span><span><span><span>-⁢b</span>±<span><span>b2</span><span><span>-4</span>⁢<span>a⁢c</span></span></span></span><span>2⁢a</span></span></span>Substitute the values <span><span>a=6</span><span>a=6</span></span>, <span><span>b=<span>−3</span></span><span>b=<span>-3</span></span></span>, and <span><span>c=<span>−1</span></span><span>c=<span>-1</span></span></span> into the quadratic formula and solve for <span>xx</span>.<span><span><span>3±<span>√<span><span><span>(<span>−3</span>)</span>2</span><span><span>−4</span>⋅<span>(<span>6⋅<span>−1</span></span>)</span></span></span></span></span><span>2⋅6</span></span><span><span>3±<span><span><span>-3</span>2</span><span><span>-4</span>⋅<span>6⋅<span>-1</span></span></span></span></span><span>2⋅6</span></span></span>Simplify.Tap for less steps...Simplify the numerator.Tap for less steps...Raise <span><span>−3</span><span>-3</span></span> to the power of <span>22</span> to get <span>99</span>.<span><span>x=<span><span>3±<span>√<span>9<span><span>−4</span>⋅<span>(<span>6⋅<span>−1</span></span>)</span></span></span></span></span><span>2⋅6</span></span></span><span>x=<span><span>3±<span>9<span><span>-4</span>⋅<span>6⋅<span>-1</span></span></span></span></span><span>2⋅6</span></span></span></span>Multiply <span>66</span> by <span><span>−1</span><span>-1</span></span> to get <span><span>−6</span><span>-6</span></span>.<span><span>x=<span><span>3±<span>√<span>9<span><span>−4</span>⋅<span>−6</span></span></span></span></span><span>2⋅6</span></span></span><span>x=<span><span>3±<span>9<span><span>-4</span>⋅<span>-6</span></span></span></span><span>2⋅6</span></span></span></span>Multiply <span><span>−4</span><span>-4</span></span> by <span><span>−6</span><span>-6</span></span> to get <span>2424</span>.<span><span>x=<span><span>3±<span>√<span>9+24</span></span></span><span>2⋅6</span></span></span><span>x=<span><span>3±<span>9+24</span></span><span>2⋅6</span></span></span></span>Add <span>99</span> and <span>2424</span> to get <span>3333</span>.<span><span>x=<span><span>3±<span>√33</span></span><span>2⋅6</span></span></span><span>x=<span><span>3±33</span><span>2⋅6</span></span></span></span>Simplify the denominator.Tap for less steps...Rewrite.<span><span>x=<span><span>3±<span>√33</span></span><span>2⋅6</span></span></span><span>x=<span><span>3±33</span><span>2⋅6</span></span></span></span>Multiply <span>22</span> by <span>66</span> to get <span>1212</span>.<span><span>x=<span><span>3±<span>√33</span></span>12</span></span><span>x=<span><span>3±33</span>12</span></span></span>The result can be shown in both exact and approximate form.<span><span>x=<span><span>3±<span>√33</span></span>12</span></span><span>x=<span><span>3±33</span>12</span></span></span><span>x≈0.72871355,<span>−0.22871355</span></span>
7 0
3 years ago
6. (4.2.12) Of the items manufactured by a certain process, 20% are defective. Of the defective items, 60% can be repaired. a. F
nata0808 [166]

Answer:

(a) Probability that a randomly chosen item is defective and cannot be repaired is 8%.

(b) Probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired is 0.2711.

Step-by-step explanation:

We are given that of the items manufactured by a certain process, 20% are defective. Of the defective items, 60% can be repaired.

Let Probability that item are defective = P(D) = 0.20

Also, R = event of item being repaired

Probability of items being repaired from the given defective items = P(R/D) = 0.60

<em>So, Probability of items not being repaired from the given defective items = P(R'/D) = 1 - P(R/D) = 1 - 0.60 = 0.40 </em>

(a) Probability that a randomly chosen item is defective and cannot be repaired = Probability of items being defective \times Probability of items not being repaired from the given defective items

              = 0.20 \times 0.40 = 0.08 or 8%

So, probability that a randomly chosen item is defective and cannot be repaired is 8%.

(b) Now we have to find the probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 20 items

            r = number of success = exactly 2

           p = probability of success which in our question is % of randomly

                  chosen item to be defective and cannot be repaired, i.e; 8%

<em>LET X = Number of items that are defective and cannot be repaired</em>

So, it means X ~ Binom(n=20, p=0.08)

Now, Probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired is given by = P(X = 2)

   P(X = 2) = \binom{20}{2} \times 0.08^{2} \times  (1-0.08)^{20-2}

                 = 190 \times 0.08^{2}  \times 0.92^{18}

                 = 0.2711

<em>Therefore, probability that exactly 2 of 20 randomly chosen items are defective and cannot be repaired is </em><em>0.2711.</em>

             

6 0
3 years ago
Please, I need your help!! I will mark correct answer as brainliest.<br>​
Marizza181 [45]

Answer:

3, -3, 0

Step-by-step explanation:

The exlcusions of x are where the denominator =0

So we can write the following equations

x²-9=0

and

5x=0

Let's solve the first one

x²-9=0

x²=9

x= ±3

and

5x=0

x=0

Therefore x cannot equal 3, -3, 0

3 0
2 years ago
Read 2 more answers
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