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77julia77 [94]
3 years ago
5

How to solve x9+y10=4

Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

if you meant 9x+10y=4 then the x intercepts are (4/9,0) and the y intercepts are (0,2/5).

Step-by-step explanation:

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State the order and type of each transformation of the graph of the function
algol [13]

Using translation concepts, compared to the graph of the base function g(x) = x², the function f(x) was:

  • Vertically stretched by a factor of 4.
  • Shifted left by 9 units.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the base function g(x) = x² was:

  • Multiplied by 4, that is, vertically stretched by a factor of 4.
  • Shifted left 9 units, as x -> x + 9.

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

6 0
2 years ago
A planet's year is the time it takes that planet to revolve around the Sun. A Mars year is 1.88 Earth years. If you are 13 years
Nata [24]
Mars year is 1.88 of your Earth years.
So if you are 13,

1.88 x 13=24.44, or 24 years old, I think.
6 0
3 years ago
Solve the system of linear equations below.
Olegator [25]

Answer:

B. x = 2, y = 6

Step-by-step explanation:

2x + 5y = 34...(1) \\  \\ x + 2y = 14 \\  \therefore \: x = 14 - 2y...(2) \\  \\ from \: equations \: (1) \: and \: (2) \\  \\ 2(14 - 2y) + 5y = 34 \\ \therefore \: 28 - 4y + 5y = 34 \\  \therefore \: 28 + y = 34 \\ \therefore \:  y = 34 - 28 \\  \huge \red{ \boxed{\therefore \:  y = 6}} \\ substituting \: y = 6 \: in \: equation \: (2) \\ x = 14 - 2 \times 6 \\ \therefore \:  x =14 - 12 \\  \huge \purple{ \boxed{\therefore \:  x =2}} \\  \\ \huge \orange{ \boxed{ \therefore \:  x  = 2, \:  \: y = 6}} \\

5 0
3 years ago
Read 2 more answers
Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a
Mashutka [201]

Answer:

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

Step-by-step explanation:

Given

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Required

Make the denominator equal

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Factorize the denominator

\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}

\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}

\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}

\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}

<em>The expression now have the same denominator</em>

7 0
3 years ago
What is the perimeter of the parallelogram?
Nesterboy [21]
P=2(a+b)=2·(4+4)=16 cm
3 0
3 years ago
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