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kvasek [131]
3 years ago
15

How were the lives of women during the early antebellum era(1800-1830)

Advanced Placement (AP)
2 answers:
Fittoniya [83]3 years ago
7 0
Horrible.. They had stay home and work on stuff while the men got to make money and do what they wanted.
Arisa [49]3 years ago
5 0
The women in this era were property of their families for all intents and purposes.
The wealthy would have servants to wait on them, dress them and keep them company. They were also made to know the proper ways of housekeeping- in that they had to know how to handle servants and host parties, manage household budgets, etc. They also would learn proper decorum- how to carry/present themselves, how to dance, needlepoint, painting, playing an instrument-such as the harp or piano, singing and being well read- but not too well read. Their fathers would arrange marriages in most cases. They had beautiful dresses tho!
If they were not free women it was a life of serving.
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uncharged particle located in the nucleus; the number of these that an atom has is equal to its mass number minus its atomic num
zzz [600]

The correct answer is Neutron

Explanation:

As shown in the diagram the sub-particles in atoms are electrons, neutrons, and protons. From these, the two types of particles that are in the nucleus or center of the atom are neutrons and protons. Moreover, neutrons differ from protons because these are neutral or are not charged. According to this, the uncharged particles in atoms are neutrons.

Moreover, the number of neutrons can be calculated by subtracting the atomic number (number of protons) to the mass number (number of atoms and protons). For example, if in an atom the mass number is 12 (protons and neutrons)and the atomic number is 6 (number of protons), the neutrons are 6 (12 - 6 = 6). According to this, the correct answer is the neutron.

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A conical water tank is 24 ft high and has a radius of 10 ft at the top. If water flows into the tank at a rate of 20 cubic feet
Akimi4 [234]

Answer:

0.027 cubic ft/min

Explanation:

Volume of water is V=V(t) Depth of water is h=h(t)

The relationship between V and h is

V=π/3.r2.h

Let

h0= the height of the cylinder = 24ft, r0= the radius of the opening = 10ft.

Since water level (h) rise with respect to flow rate we find an expression for r and substitute into V

r/h = r0/h0= 10/24 = 5/12

r = (5/12) h,

Substitute for r in V

so,

V=1/3.π.(h2)square = 1/3.π. 25/144.(h3)

When

h= 16ft

and dV/dt = 20ft3/min

,

dV/dt =1/3*π*25/144*h3*(dh/dt)

20ft3/min= 1/3*π* 25/144*h3*(dh/dt)

20 = 1/3*π*(16)3.(dh/dt)

Make dh/DT subject of formula

dh/dt=(20*3*144)/(25*π*4096) = 8640/321740.8

=

dh/dt= 0.027 ft3/min

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