Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
Answer:
perimeter of rectangle= 2(4+X)
32=8+2x
32-8=2x
26=2x
26/2=X
14=X
perimeter of triangle=3×sides
20=3x
20/3=X
6.66=x
Answer:
look around the bottom of the page and if it has something like a brand or company whatever write it down in the search and then write the title of the paper and look for pdfs
