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Lisa [10]
3 years ago
7

Write an algorithm which gets a number A, if it is even, prints even, and if it is odd prints odd.

Computers and Technology
1 answer:
juin [17]3 years ago
7 0

Answer:

The algorithm to find A is even or odd.

  1. input A.
  2. Check the remainder on diving by 2 by A%2.
  3. If remainder is 1 then A is odd Print(Odd).
  4. If remainder is 0 print(Even).

Explanation:

To check if the number is even or odd we use modulo  operator(%).Which gives the remainder on dividing.So if we do this A%2 it will give the remainder that will come out on dividing the value of A by 2.

So if the remainder comes out is 1 then the number is odd and if the remainder is 0 then the number is odd.

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Explanation:

#include <iostream>

using namespace std;

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   string ItemName[3]={" "," "," "};

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// You can run this after compiling without any problem.

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True

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katen-ka-za [31]

Answer:

import java.util.Scanner;

public class BasicInput {

   public static void main(String[] args) {

       //Create an object of the Scanner class

       Scanner scnr = new Scanner(System.in);

       

       //Define int and double variables

       int userInt;

       double userDouble;

       

       //Define char and string variables similarly

       char userChar;

       String userString;

       

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}

Sample Output:

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Enter char:

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