Answer:
Explanation:
The following class is written in Java. I created the entire Circle class with each of the methods and constructor as requested. I also created a tester class to create a circle object and call some of the methods. The output can be seen in the attached picture below for the tester class.
class Circle {
double radius;
public Circle(double radius) {
this.radius = radius;
}
public double getRadius() {
return radius;
}
public void resetRadius() {
radius = 0;
}
public double calculateArea() {
double square = Math.pow((Math.PI * radius), 2);
return square;
}
}
Answer:
C. BMP
Explanation:
BMP is a simple bitmap image format developed by Microsoft and IBM.
It's used almost exclusively on the Microsoft Windows operating system these days, was used on OS/2. It's the format the basic MS Paint program, that comes with Windows, edits its file in.
It's also a basic graphic format to use for programmers.
Of course GIF, PDF, TIFF and PNG are also used on Windows, as well as on most other operating system.
Answer:
See explanation below
Explanation:
Previos concepts
First Come First Serve (FCFS) "is an operating system scheduling algorithm that automatically executes queued requests and processes in order of their arrival".
Shortest job next (SJN), or the shortest job first (SJF) or shortest "is a scheduling policy that selects for execution the waiting process with the smallest execution time".
Shortest remaining time (SRF) "is a scheduling method that is a preemptive version of shortest job next scheduling'".
Round robin (RR) is an algorithm where the time parts "are assigned to each process in equal portions and in circular order, handling all processes without priority"
Solution for the problem
Assuming the dataset given on the plot attached.
Part a
For this algorithm the result would be:
Job A 0-6
Job B 6-(6+3) = 6-9
Job C 9-(9+1) = 9-10
Job D 10-(10+4) = 10-14
Part b
For this algorithm the result would be:
Job A 0-6
Job C 6-(6+1) = 6-7
Job B 7-(7+3) = 7-10
Job D 10-(10+4) = 10-14
Part c
For this algorithm the result would be:
Job A 0-1 until 14
Job B 2-(2+3) = 2-5
Job C 3-(3+2) = 3-5
Job D 9-(9+5) = 9-14
Part d
For this algorithm the result would be:
Job A 0-2 , 7-9, 12-14
Job B 2-4, 9-10
Job C 4-(4+1) = 4-5
Job D 5-7, 10-12
Answer:
// code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int length=10,height=7,width=5;
// find the volume of
int vol=length*height*width;
// find the surface area
int sa=2*(length*width+length*height+height*width);
// find the perimeter
int peri=4*(length+width+height);
// print the volume
cout<<"Volume is: "<<vol<<" cm^3."<<endl;
// print the surface area
cout<<"Surface area is: "<<sa<<" cm^2."<<endl;
// print the perimeter
cout<<"Perimeter is: "<<peri<<" cm."<<endl;
return 0;
}
Explanation:
Declare and initialize length=10, width=5 and height=7.calculate volume by multiply length, width and height and assign to variable "vol".Then find the surface area as 2*(length*width+length*height+height*width) and assign it to variable "sa".Then find the perimeter as 4*(length+width+height) and assign to variable "peri". Print the volume, perimeter and surface area.
Output:
Volume is: 350 cm^3.
Surface area is: 310 cm^2.
Perimeter is: 88 cm.
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