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Vladimir [108]
3 years ago
14

How do you solve 3k+2(5k-3)=7

Mathematics
1 answer:
slamgirl [31]3 years ago
8 0

3k+2(5k-3)=7

=>3k+10k-6=7

=>13k=13

=>k=13/13

Therefore, k=1

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Answer:

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Step-by-step explanation:

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y+1=-3(x-5)\\y+1=-3x+15\\y=-3x+15-1\\y=-3x+14

<em>We know that the perpendicular line would have a slope (m) that is </em><em>negative reciprocal </em><em>of this (\frac{1}{3}). Thus we can write the perpendicular line's equation as  y=\frac{1}{3}x+b. </em>

<em />

<em>Now putting x = 4 and y = -6 into the equation, we can solve for b:</em>

<em>y=\frac{1}{3}x+b\\-6=\frac{1}{3}(4)+b\\-6=\frac{4}{3}+b\\b=-6-\frac{4}{3}\\b=-\frac{16}{3}</em>

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Thus, the equation of the perpendicular line is  y=\frac{1}{3}x-\frac{16}{3}

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Answer:

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Answer:

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