Answer:
80
Step-by-step explanation:
Answer:
6 socks
Step-by-step explanation:
What we must do is calculate the probability of this happening, that he takes out two black socks in the first two taken out.
There are 12 black socks and in total they are 24, therefore the probability of drawing 1 is:
12/24
and now the probability of getting another one is 11 (there is one less outside) and in total they are 23:
11/23
the final probability is the multiplication of these events:
(12/24) * (11/23)
P = 0.24
Now, to know how many you should get, we multiply the probability by the total number of socks, that is:
0.24 * 24 = 5.76
So you must take out at least 6 socks for the above to happen.
Answer:
Dimensions :
x (the longer side, only one side with fence ) = 90 ft
y ( the shorter side two sides with fence ) = 45 ft
Total fence used 45 * 2 + 90 = 180 ft
A(max) =
Step-by-step explanation: If a farmer has 180 ft of fencing to encloses a rectangular area with fence in three sides and the river on one side, the farmer surely wants to have a maximum enclosed area.
Lets call "x" one the longer side ( only one of the longer side of the rectangle will have fence, the other will be along the river and won´t need fence. "y" will be the shorter side
Then we have:
P = perimeter = 180 = 2y + x ⇒ y = ( 180 - x ) / 2 (1)
And A (r) = x * y
A(x) = x * ( 180 - x ) /2 ⇒ A(x) = (180/2) *x - x² / 2
Taking derivatives on both sides of the equation :
A´(x) = 90 - x
Then if A´(x) = 0 ⇒ 90 - x = 0 ⇒ x = 90 ft
and from : y = ( 180 - x ) / 2 ⇒ y = 90/2
y = 45 ft
And
A(max) = 90 * 45 = 4050 ft²
Answer:
The triangles are congruent by Angle Side Angle congruency statement and the reason is below.
Step-by-step explanation:
Given:
∠ VUW ≅ ∠ XYW
VW ≅ YW
To Prove:
Δ VUW ≅ Δ XYW
Proof:
In Δ VUW and Δ XYW
∠ VUW ≅ ∠ XYW ……….{Given}
VW ≅ YW ............{Given}
∠ VWU ≅ ∠ XWY …………..{Vertically Opposite Angles are equal}
Δ VUW ≅ Δ XYW .….{ By Angle-Side-Angle congruence test}
......Proved
Answer:
Step-by-step explanation:
$870.57
use equation total = Principal(1 + rate*time)
