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Alexeev081 [22]
3 years ago
14

Determine the intercepts of the line.

Mathematics
2 answers:
mojhsa [17]3 years ago
8 0
The y-intercept is where the line intercepts the y-axis, or the vertical axis

In this case, the y-intercept is

(0, 0.4)

The x-intercept is where the line intercepts the x-axis, or the horizontal axis.

In this case, the x-intercept is:

(0.3, 0)

Hope this helps :)
mamaluj [8]3 years ago
6 0

Answer:

y intercept: (0,4)

x intercept:(0,3)

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Answer:

(a) The mean or expected value of <em>X </em>is 2.2.

(b) The standard deviation of <em>X</em> is 1.3.

Step-by-step explanation:

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The probability distribution of <em>X</em> id provided.

The formula to compute the mean or expected value of <em>X </em>is:

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The formula to compute the standard deviation of <em>X </em>is:

\sigma=\sqrt{E(X^{2})-(E(X))^{2}}

The formula of E (X²) is:

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(a)

Compute the expected value of <em>X</em> as follows:

E(X)=\sum x.P(X=x)\\=(0\times0.06)+(1\times0.25)+(2\times0.35)+(3\times0.15)+(4\times0.13)+(5\times0.06)\\=2.22\\\approx2.2

Thus, the mean or expected value of <em>X </em>is 2.2.

(b)

Compute the value of E (X²) as follows:

E(X^{2})=\sum x^{2}.P(X=x)\\=(0^{2}\times0.06)+(1^{2}\times0.25)+(2^{2}\times0.35)+(3^{2}\times0.15)+(4^{2}\times0.13)+(5^{2}\times0.06)\\=6.58

Compute the standard deviation of <em>X</em> as follows:

\sigma=\sqrt{E(X^{2})-(E(X))^{2}}\\=\sqrt{6.58-(2.22)^{2}}\\=\sqrt{1.6516}\\=1.285\\\approx1.3

Thus, the standard deviation of <em>X</em> is 1.3.

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