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3 years ago

What is an x-intercept

Mathematics

2 answers:

sergeinik [125]3 years ago

8 0

An x-intercept is the poin where a graph that intercepts the x-axis. The graph can be a linear function (a line), a quadratic function (a parabola), Higher degree functions and so on.

lisabon 2012 [21]3 years ago

6 0

The x-intercept is the point where a line crosses the x-axis. So the x-intercepts for the 3 lines shown in the image provided are (-5,0), (-1,0), and (3, 0). Notice that all x-intercepts have a y-coordinate of zero.

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The height H of a skydiver t seconds after jumping. Let T be the independent variable, and assume the skydiver jumps from a heig

Rina8888 [55]

Answer:

25 seconds

Step-by-step explanation:

Skydiving.

height (in feet) above the earth=h(t)= -16t^2 + 10,000

the time it would take to fall when h is 0

-16t^2 + 10,000=0

-16t^2=-10000

16t^2=10000

t^2=10000/16=625

t=sqrt 625=25 seconds

6 0

2 years ago

7n2 + 5 = 453 Solve the quadratic function

Reptile [31]

7n^2 + 5 = 453

Subtract 5 from both sides:

7n^2 = 448

Divide both sides by 7:

N^2 = 64

Take the square root of both sides:

N = 8

8 0

3 years ago

Read 2 more answers

Please help! I’ll mark brainliest

Usimov [2.4K]

Answer: 19 ≥ 3z + 1 ≥ - 5

8 0

2 years ago

For an angle 0 with the point (-20,-21) on its terminating side, what is the value of cosine ?

Karo-lina-s [1.5K]

check the picture below.

$\bf (\stackrel{a}{-20},\stackrel{b}{-21})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{-20}\\ b=\stackrel{opposite}{-21}\\ \end{cases} \\\\\\ c=\sqrt{(-20)^2+(-21)^2}\implies c=\sqrt{841}\implies c=29 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-20}}{\stackrel{hypotenuse}{29}}~\hfill$

5 0

2 years ago

The number of calories you burn depends on your weight. A 160-pound person burns 237 calories during 30 minutes of tennis. Find

larisa [96]

Answer:

A 190-pound person would burn 285 calories at the same rate.

Step-by-step explanation:

Calories burn depends on the weight

Weight of first person = 160

Calories burn for 160 pounds in 30 mins = 237

Calories burn rate for 1 pound in 30 mins = $\frac{237}{160}$ = 1.5

Calories burn for 190 Pound person would be:

Weight of second person = 190

Calories burn for 190 pounds in 30 min:

As the burn rate of calories is same for the two persons:

= rate × weight

= 1.5 * 190

= 285 calories

5 0

3 years ago