we know that given terms were i geometric progression.
which means common ratio is same between two consecutive terms .
here we have 8,40,200,1000.
we know that common ratio =second term/first term =40/8=5.
so each and every terms is multiplied by 5 to get next term for this series the term after 1000 is 5000 =1000*5.
in part b we have another series which is having common ratio of -2.
so we need to multiply with -2 to find next term.
80*(-2)=-160.
for part c the common ratio is -2 .
so we need to multiply with -2 *previous term =-2*16 =-32.
Answer:
The pairs of functions that best represent the equation are f(x)=x² and g(x)=1/x
Step-by-step explanation:
For this problem, you will have to multiply each equation in the answer choices until you find the pair that has a product of x.
Let's start with the first answer choice.
(f * g)(x)
<em>f(x)=x²</em>
<em>g(x)=1/x</em>
Now, we multiply these terms together.
x² * 1/x = x²/x
Now, divide x from x². When you are dividing exponents, the exponential numbers subtract. So, since there is no exponent on x, then we assume this exponent to be 1. So, when dividing you will subtract 1 from 2.
x²/x = x
So, the answer to the problem is answer choice A. These functions multiply together to get you a final product of x.
9514 1404 393
Answer:
Step-by-step explanation:
A graphing calculator answers these questions easily.
The ball achieves a maximum height of 40 ft, 1 second after it is thrown.
__
The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.
h(t) = -16(t^2 -2t) +24
h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square
h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form
Compare this to the vertex form:
f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'
We see the vertex of our height equation is ...
(h, k) = (1, 40)
The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.
To reduce the radical, you have to factorize 108.
108 is a multiple of 3, so to factorize it, you can divide it by 3
You can rewrite the square root as:
![\sqrt[]{3\cdot36}=\sqrt[]{3}\cdot\sqrt[]{36}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%5Ccdot36%7D%3D%5Csqrt%5B%5D%7B3%7D%5Ccdot%5Csqrt%5B%5D%7B36%7D)
The square root of 36 is equal to 6 so you can write the expression as:
![\sqrt[]{3}\cdot\sqrt[]{36}=6\sqrt[]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%7D%5Ccdot%5Csqrt%5B%5D%7B36%7D%3D6%5Csqrt%5B%5D%7B3%7D)
