Prophase I
The chromosomes condense, and the nuclear envelope breaks down & crossing-over occurs.
Metaphase I
Pairs of homologous chromosomes move to the equator of the cell.
Anaphase I
Homologous chrmosomes move to the oppisite poles of the cell.
Telophase I and Cytokinesis
Chromosomes gather at the poles of the cells & the cytoplasm divides.
Prophase II
A new spidle forms around the chromosomes.
Metaphase II
Chromosomes line up at the equator.
Anaphase II
Centromeres divides & chromatids move to the opposite poles of the cells.
Telophase II and Cytokinesis
A nuclear envelope forms around each set of chromosomes & the cytoplasm divides.
Answer: If this population were in equilibrium and if the sickle-cell allele is recessive, the proportion of the population susceptible to sickle-cell anemia under typical conditions should be 0.20
Explanation: Hardy-Weinberg law provides an equation to relate genotype frequencies and allele frequencies in a randomly mating population. The equation is;
p² + 2pq + q² = 1
For 2 alleles such as A and a, where
p² = homozygous dominant
q² = homozygous recessive and
2pq = heterozygous
From the question, it is said that the sickle-cell allele (SS) constitutes 20% (that is, 20/100) of the hemoglobin alleles in the human gene pool and it is also said to be the homozygous recessive allele.
Therefore, q² = 20/100 = 0.20
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1. No credible source
2. Check if its a biased answer
3. Examine evidence
