Let the second car meets the first car after n hours.
Second car starts with 8km/h, After succeeding hours his speed increases by 0.5 km.
So, Distance travelled by second car = 8 + 8.5 + 9
..... 8+(n-1) 0.5.....(1)
eqn. (1) sum of n terms Of A.P with first term 8
and common difference 0.5.
Sum of all the terms in equation 1 is also equals to the distance travelled by the first car for n hours, i.e. 10n km .
Now, we have (n/2) {16+(n-1) 0.5} = 10n........(2)
From equation (2) we get, n= 9
Hence, Both the cars will meet after 9 hours.
Hope it helps!
Answer:
y=0
Step-by-step explanation:
Reorder the terms:
2 + -1(2 + y) = 3y
2 + (2 * -1 + y * -1) = 3y
2 + (-2 + -1y) = 3y
Combine like terms: 2 + -2 = 0
0 + -1y = 3y
-1y = 3y
Solving
-1y = 3y
Add '-3y' to each side of the equation.
-1y + -3y = 3y + -3y
Combine like terms: -1y + -3y = -4y
-4y = 3y + -3y
Combine like terms: 3y + -3y = 0
-4y = 0
Divide each side by '-4'.
y = 0
hope this helps
Answer:
The answer is C
Step-by-step explanation:
12+8=20
Then you subtract 20 by 5
Answer:
B. 80 cm^2
Step-by-step explanation:
A = bh/2
A = (FE)(16 cm)/2
A = (10 cm)(16 cm)/2
A = 80 cm^2
There are .3 decimeters in 3 centimeters
