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Troyanec [42]
3 years ago
11

There were 200,000 animals of a certain species in 1980. Since then,this number has decreased by 4.5% each year. Approximately h

ow many animals of this species will be left in 2025?
Mathematics
2 answers:
g100num [7]3 years ago
8 0

Answer: Approximately 25187 animals of this species will be left in 2025

Step-by-step explanation:

We would apply the formula for exponential decay which is expressed as

y = b(1 - r)^x

Where

y represents the population of animals after x years.

x represents the number of years.

b represents the initial population of animals.

r represents rate of decay.

From the information given,

b = 200000

r = 4.5% = 4.5/100 = 0.045

x = 2025 - 1980 = 45 years

Therefore,

y = 200000(1 - 0.045)^45

y = 200000(0.955)^45

y = 25187

Anni [7]3 years ago
4 0

Answer:

There'll be approximately 25187.3059 animals of this species in 2025.

Step-by-step explanation:

In this case we have a compounded interest problem, but the interest rate is negative, since the number will be decreasing. To solve it we can use the compound interest formula shown bellow:

M = C*(1 + r)^(t)

Where M is the final amount, C is the initial amount, r is the interest rate and t is the time elapsed.

In this case the time elapsed was from 1980 to 2025, so 45 years. Applying the data to the formula gives us:

M = 200000*(1 + (-0.045))^(45)

M = 200000*(1 - 0.045)^(45)

M = 200000*(0.955)^(45)

M = 25187.3059

There'll be approximately 25187.3059 animals of this species in 2025.

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fomenos

Answer:

x³+57

step by step explanation

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3 years ago
The price of a European tour includes stopovers at five cities to be selected from 15 cities. In how many ways can a traveler pl
xeze [42]

Answer:

The traveler can plan such a tour in 3003 ways.

Step-by-step explanation:

The order that the cities are chosen is not important, since it is chosen by the company and not by the traveler. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this problem, we have that:

Combinations of 5 cities from a set of 15. So

C_{15,5} = \frac{15!}{5!10!} = 3003

The traveler can plan such a tour in 3003 ways.

4 0
3 years ago
Find the measure of the hands of a clock at 12:38
Vinvika [58]
I would say 12 hours and 38 min
8 0
3 years ago
Angle K in △MKL is a right angle.
wel
  1. Hypotenuse= ML
  2. Perpendicular=KL=15
  3. Base= KM=8

By using Pythagoras theorem.

  • h²=p²+b²
  • ML²=15²+8²
  • ML²=225+64
  • ML=√289

Therefore ML= 17...

Step-by-step explanation:

Hope it helps....Mark me brilliant

4 0
2 years ago
Several years​ ago, 38​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
Colt1911 [192]

Answer:

0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995

0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values are:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The estimated proportion of people satisfied with the quality of education the students receive is given by:

\hat p =\frac{499}{1165}= 0.428

The confidence interval for the proportion if interest is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing the info given we got:

0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995

0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

8 0
3 years ago
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