A proof in which you assume the opposite of what you want to prove
1 answer:
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2x + 8 > 10
You first move + 8 to the other side, so you subtract 8
(When you see addition, you perform subtraction)
2x + 8 - 8 > 10 - 8
+ 8 and - 8 cancels out
2x > 2
Now, to isolate x, you should divide both sides by 2
(When you see multiplication, you perform division)
> 
2 and 2 cancels out and we are left with
x > 1
So your final answer will be x > 1
You first move + 8 to the other side, so you subtract 8
(When you see addition, you perform subtraction)
2x + 8 - 8 > 10 - 8
+ 8 and - 8 cancels out
2x > 2
Now, to isolate x, you should divide both sides by 2
(When you see multiplication, you perform division)
2 and 2 cancels out and we are left with
x > 1
So your final answer will be x > 1