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Andreas93 [3]
3 years ago
10

Keith is the team manager for his school's soccer team. He is ordering team uniforms for the upcoming season. • Uni-Fit charges

$19.99 per uniform and $30 for packing and shipping. • All-Forms charges $14.99 per uniform and $50 for packing and shipping. Which inequality should Keith use to find n, the minimum number of uniforms that can be ordered so that the total cost at Uni-Fit is less than the total cost at All-Forms? A. 19.9977 80 < 14.9911 | 50 B. 19.99 307 > 14.99-50n C. 19.997 50 14.999 30 D. 19.99 507 14.99 30n​ please help me ASAP please and thank you so much
Mathematics
1 answer:
Alinara [238K]3 years ago
6 0
The answer is C hope this help
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I need the answer ASAP thank you very much!!!!!
umka21 [38]
HI THERE LET ME HELP U WITH YOUR QUESTION

**PERFECT SQUARES ARE POSITIVE INTEGERS**<span>
</span>THE NUMBERS CANNOT INCLUDE ITSELF AND ALWAYS SHOULD HAVE A ONE IN IT. 

2.89 AND 0.004 ARE PERFECT NUMBERS. THEY INCLUDE 1 AND THEY DONT INCLUDE ITSELF

HOPE IT HELPS  

 

8 0
3 years ago
Tracy has a cell phone plan that provides 250 free minutes each month for a flat rate of 29$. For any minutes over 250 tracy us
iVinArrow [24]

Answer:

Since Tracy is charged $29 for 250 free minutes so:

For x ≤ 250, f(x) = $29

tracy is charged an extra $0.35 per minute for calls over 250 minutes, so:

For x ≥ 250, f(x) = 29 + 0.35(x - 250)

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2 years ago
Which terms shown is not a method of estimating
Rainbow [258]
The judge to be probable shown is not a method
3 0
3 years ago
How many cubes of side 2cm can be fitted into a box 12 cm long, 8cm wide and 4cm high?
kogti [31]

Answer:

there are 48cubes fetted into a box

6 0
3 years ago
Read 2 more answers
Find the derivative.
krek1111 [17]

Answer:

\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

  • Expanding/Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \frac{\sqrt{x}}{e^x}

<u>Step 2: Differentiate</u>

  1. Derivative Rule [Quotient Rule]:                                                                   \displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}
  2. Basic Power Rule:                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}
  3. Exponential Differentiation:                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}
  4. Simplify:                                                                                                         \displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}
  5. Rewrite:                                                                                                         \displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}
  6. Factor:                                                                                                           \displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
2 years ago
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