17. The length of a rectangle is 12 in, and the perimeter is 56 in. Find the width of the rectangle.
1 answer:
Answer:
Step-by-step explanation:
P = 2(L + W)
P = 56
L = 12
now sub...we are looking for w
56 = 2(12 + W)
56 = 24 + 2W
56 - 24 = 2W
32 = 2W
32/2 = W
16 = W <==== the width is 16 inches
check...
P = 2(L + W)
56 = 2(12 + 16)
56 = 2(28)
56 = 56 (correct)
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