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nikitadnepr [17]

4 years ago

11

Of 150 random customers, 63 ordered ham, 73 ordered turkey, and the rest ordered rast beef. Based upon the results, hownmany of

the next 75 customers would yu expect to order roast beef?

2 answers:

Mrrafil [7]4 years ago

4 0

Answer:

7

Step-by-step explanation:

12 people would be predicted to have roast beef because 73+63=136 and then 150-136=14divided by 2 equals 7

IgorLugansk [536]4 years ago

4 0

Answer:

7

Step-by-step explanation:

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sweet [91]

1 3/4 for each batch to make 2 1/2 batches you need to take the amount of raisins for one batch 1 3/4 and multiply it by 2 1/2 the amount of batches.

1 3/4*2 1/2= 4 3/8 cups of raisins

4 0

4 years ago

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A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th

Olegator [25]

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

$y = \frac{340110}{1 + 377e^{-0.259t}}$

Solving (a): 1998

Year 1998 means that:

$t =1998 - 1980$

$t =18$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*18}}$

$y = \frac{340110}{1 + 377e^{-4.662}}$

$y = \frac{340110}{1 + 3.562}$

$y = \frac{340110}{4.562}$

$y = 74553$ --- approximated

Solving (b): 2003

Year 2003 means that:

$t = 2003 - 1980$

$t =23$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*23}}$

$y = \frac{340110}{1 + 377e^{-5.957}}$

$y = \frac{340110}{1 + 0.976}$

$y = \frac{340110}{1.976}$

$y = 172120$ --- approximated

Solving (c): 2006

Year 2006 means that:

$t = 2006 - 1980$

$t =26$

So, we have:

$y = \frac{340110}{1 + 377e^{-0.259*26}}$

$y = \frac{340110}{1 + 377e^{-6.734}}$

$y = \frac{340110}{1 + 0.4485}$

$y = \frac{340110}{1.4485}$

$y = 234802$ --- approximated

3 0

3 years ago

Based on the data in the two-way table, the probability of being 25-35 years and having a hemoglobin level above 11 is __ a.29 b

Alina [70]

The probability of being 25-35 years and having a haemoglobin level above 11 is 34%.

The probability of having a haemoglobin level above 11 is 36%.

Being 25-35 years and having a hemoglobin level above 11 are not dependent on each other.

<h3>What are the probabilities?
</h3>

Probability determines the odds that a random event would occur. The odds of the event happening lie between 0 and 1.

The probability of being 25-35 years and having a haemoglobin level above 11 = number of people between 25 - 35 that have a level above 11 / total number of people between 25 - 35

44 / 128 = 34%

The probability of having a haemoglobin level above 11 = number of people with a level above 11 / total number of respondents

153 / 429 = 36%

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

4 0

2 years ago

Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

3 years ago

What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?

Deffense [45]

So you have a right angle triangle. You need to use trig for this, as you have two values you can figure out a third.

You know that you have

90 deg. angle
19 deg. angle
Therefor you have 71 deg. angle

sin19 = x/15
15sin19 = x
x = 2.2

Now do Pythagoras c^2-b^2=a^2

a = 14.8

So the sides are 2.2 and 14.8 units long. (If these numbers are wrong tell me and I'll edit answer)

7 0

3 years ago

Read 2 more answers