The answer is a, because the absolute value of x(the actual weight of the product) minus the target weight of 18.25 needs to be greater that the target weight difference of .36 so that it is outside the range. So basically, any number outside of the range will be correct.You can plug in number that you know are in/ out of the acceptable range of numbers for this problem in.
|18.62-18.25|>.36
.37>.36
18.62 is not in range.
Answer:
t(c) = 3.355
Step-by-step explanation:
We assume a normal distribution, and with sample size n = 9 we should follow a t -student test on both tails since the FDA is interested in determining if the amount of drug absorbed is different from 3.5 micrograms.
Therefore if α = 0,01 that means that confidence interval is 99 % or 0,99
Finally with α/2 = 0,005 and 8 degrees of freedom we find in t-student table t(c) = 3.355
Answer:
A)5 is the answer
Step-by-step explanation:
this is the answer
