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3 years ago

(N * 3) + 6 - (n * 2) = n + 3 what is value of n

Mathematics

2 answers:

Nuetrik [128]3 years ago

8 0

$n\cdot 3+6-n\cdot2=n+3\\
3n+6-2n=n+3\\
6=3\\
n\in\emptyset
$

GalinKa [24]3 years ago

7 0

(n*3)+6-(n*2)=n+3
3n+6-2n=n+3
3n-2n-n=3-6 every n on the left and free numbers on the right
0=-3
contradiction, there are no solution

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A drink is made by mixing pineapple juice , orange juice and line juice in the ratio 2:7:3 Sally makes 600ml of the drink

Tresset [83]

Sally has 600 ml of drink
Karen has 600 ml of lime juice

When it is mixed at a ratio of 2:7:3 . . .pineapple:orange:lime (respectively) . . this means . . . there are a total of 2 + 7 + 3 parts = 12 parts . . and each part individually is as follows:

pineapple = 2/12
orange = 7/12
lime = 3/12

Sally has 12 parts = 600 ml of drink
. . pineapple = 2/12*600ml = 100 ml pineapple
. . orange = 7/12*600ml = 350 ml orange
. . lime = 3/12*600ml = 150 ml lime

We know Karen has 600 ml of lime juice and if that is 3/12 of the total, then 600*12/3 = the total drink = 2400 ml of drink

Karen has 12 parts = 2400 ml of drink
. . pineapple = 2/12*2400ml = 400 ml pineapple
. . orange = 7/12*2400ml = 1400 ml orange
. . lime = 3/12*2400ml = 150 ml lime

Thus . . . (for Karen) . . .
A = 2400 ml of drink
B = 400 ml of orange juice
C = 1400 ml of pineapple juice

5 0

3 years ago

Marlina received her salary on Friday. She spent one-half of her salary on rent and then spent $338 on her electric and water bi

Alenkinab [10]

Answer:

$654

Step-by-step explanation:

Let the amount of money Marlina's received for her salary be x.

We know that she spent 1/2 of her salary on rent and then $338 on her electric and water bill. So, after this, she will have:

$x-\frac{1}{2}x-338$

Left of her salary.

Next, she spent one half of what was left. So, it will be one-half of the equation. Therefore, she will have spent:

$x-\frac{1}{2}x-338-\frac{1}{2}(x-\frac{1}{2}x-338)$

Finally, she spent $56 for gas. So, we will subtract 56:

$x-\frac{1}{2}x-338-\frac{1}{2}(x-\frac{1}{2}x-338)-56$

And we know that after all of the expenses, she will have $102 left. Therefore:

$x-\frac{1}{2}x-338-\frac{1}{2}(x-\frac{1}{2}x-338)-56=102$

We want to know how much Marlina spent on rent. So, let's find her salary x first.

First, let's distribute the 1/2:

$x-\frac{1}{2}x-338-\frac{1}{2}x+\frac{1}{4}x+169-56=102$

Combine like terms:

$(x-\frac{1}{2}x-\frac{1}{2}x+\frac{1}{4}x)+(-338+169-56)=102$

Evaluate:

$\frac{1}{4}x-225=102$

Add 225 to both sides:

$\frac{1}{4}x=327$

Multiply both sides by 4:

$x=\$ 1308$

Therefore, Marlina received a total of $1308 for her salary.

We know that she spent half of her salary on rent. Therefore, the amount she spent on rent is:

$r=\frac{1}{2}(1308)=\$ 654$

And we're done!

7 0

3 years ago

Tom brought 7/8 gallons of water to a party and his friends drank2/3 of it. How many gallons of water did they drink?

natka813 [3]

In plain and short, what's 2/3 of 7/8? well, is just their product.

$\bf \cfrac{7}{8}\cdot \cfrac{2}{3}\implies \cfrac{7\cdot 2}{8\cdot 3}\implies \cfrac{14}{24}\implies \stackrel{simplified}{\cfrac{7}{12}}$

5 0

3 years ago

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. Th

finlep [7]

Question:

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. The top one is labeled Class. Minimum at 70, Q1 at 74, median at 83, Q3 at 92, maximum at 100. The bottom box plot is labeled Exam. Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95. Which of the following best describes the information about the medians? (1 point) Group of answer choices

•The exam outlier at 60 makes the IQR narrower and the median higher.

•The class data is more evenly spread, which pulls its median down.

•The class median is lower than the exam median.

•The class Q3 is higher than the exam Q3.

Answer:

•The class Q3 is higher than the exam Q3.

Step-by-step explanation:

In the question we have two box plots

a) Box plots for class is given as

Minimum at 70, Q1 at 74, median at 83, Q3 at 92,

b) Box plots for exam is given as Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95.

When we compare the median of the class which is 83 and the median of the exam plots 87, we can see that the median of the exam is higher than the median of the class, hence the option

"•The class median is lower than the exam median". is wrong.

From the options given, the only correct option which best describes the information about the medians is

"•The class Q3 is higher than the exam Q3".

This is because when we compare the Q3 of the class which is 92 to the Q3 of the box which is 91 , we can see that the class Q3 is higher than the box Q3 hence the option is correct.

8 0

3 years ago

Please help the question is attatched

raketka [301]

Answer:

Step-by-step explanation:

It’s C

7 0

3 years ago