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Rufina [12.5K]
2 years ago
11

The graph of y=tan{1/4(x-pi/2)}+1 is shown what is the period of the function

Mathematics
2 answers:
irina [24]2 years ago
8 0

Answer:

The <u>period</u> is : 4pi

The <u>asymptotes</u> are: 5pi/2 + 4npi

The <u>x-intercepts</u> are: 7pi/2 + 4npi

I had a hard with this assignment, so here are the answers for the whole thing:

1.) [A]   vertical shift

2.) [D]  horizontal stretch

3.) given in the original answer

4.) [C]   y = 3tan(x) + 2

5.)  reflected across the x-axis

     shifted 3 units down

     stretched vertically

     shifted 4 units left

6.)  [D]   y = -tan(x - pi/2)

7.)Start by graphing the tangent function.Compress the graph horizontally by making the period one-half pi.Reflect the graph over the x-axis.Shift the graph up 3 units

vitfil [10]2 years ago
7 0

\pi \div  \frac{1}{4}  = 4\pi
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