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8090 [49]
3 years ago
12

One car traveled 240 miles and drove 20 mph hour faster than a second car drove 160 miles. If the cars were traveling for the sa

me time, how fast was the first car driving?
a. 90 mph
b. 80 mph
c. 50 mph
d. 60 mph
Mathematics
2 answers:
Naddik [55]3 years ago
5 0
The answer is D because car 1 drove 20 mph faster than car 2. If car 1 drove at 60 mph for 4 hours it reaches 240 miles. Car 2 at 40 mph would travel 160 in 4 hours.
marin [14]3 years ago
4 0

Answer:

d.

Step-by-step explanation:

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Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
2 years ago
Find the solutions to x2 = 20.
Gemiola [76]

Answer:

B.

Step-by-step explanation:

x^2=20; \ => \ \left[\begin{array}{ccc}x=\sqrt{20} \\x=-\sqrt{20} \end{array} \ => \ \left[\begin{array}{ccc}x=2\sqrt{5} \\x=-2 \sqrt{5} \end{array}

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2 years ago
The price of an item is reduced 70% the original price $90 what is the price now?
uranmaximum [27]
90 - (90 × .7) = $27

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7 0
3 years ago
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The product of a number and its _____ is one.<br><br>Please fill in the blank.
asambeis [7]
Itself should go in the blank

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3 years ago
What is the missing constant term in the perfect square that starts with x^2-12x
Ipatiy [6.2K]

Essentially, we are trying to find the missing constant term of (x - a)^2 (remember that we are subtracting a due to the negative sign in front of the second term). Let's expand this to see what we can work with:

(x - a)^2

  • Set up

x^2 - ax - ax + a^2 = x^2 - 2ax + a^2

  • FOIL and simplify

Now, we know the second term is 12x, so let's set the second term in the polynomial we just found equal to 12x:

2ax = 12x

  • Set up

2a = 12

  • Divide both sides of the equation by x

a = 6

  • Divide both sides of the equation by 2

We have found a = 6. We know the missing constant term is a^2, according to the polynomial we found earlier. Thus, the missing term is:

a^2 \Rightarrow 6^2 = 36


The missing constant term is 36.

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3 years ago
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