Answer:
The volume of a cone is 1 3 π r 2 h \frac { 1 } { 3 } \pi r ^{ 2 } h 31πr2h, where r denotes the radius of the base of the cone, and h denotes the height of the cone.
Step-by-step explanation:
(happy to help)
The right angles triangle has three sides including the hypotenuse which is opposite to the right angle.
If the hypotenuse - H
Then one side is - H - 2
Third side is 7 cm shorter then H-2
Therefore it’s H -2-7 = H -9
According to Pythagoras theorem
Square of hypotenuse = sum of the squares of the other 2 sides
H² = (H-9)² + (H-2)²
H² = H² -18H + 81 + H² -4H + 4
0 =H² -22H +85
This is a quadratic equation
0 = H² - 17H -5H +85
0 = H (H - 17) -5(H-17)
(H-17) (H-5) =0
H -17=0 or H-5=0
H could be 17 cm or 5 cm
If H =5 cm then
Side 1 -H-2 = 3 cm
And side 2 - H-9 = -4 cm
Since lengths cannot be negative values
H isn’t 5 cm
Therefore H =17 cm
1 side is H-2 = 15 cm
2nd side H -9 = 8 cm
Three sides are 17 cm, 15 cm and 8 cm
Ok here it is:
4x-5y=40
2x+10y=20
I used the second equation and decided to get x
2x+10y=20
Subtract 10y from both sides.
2x=-10y+20
Divide both sides by 2
x=-5y+10
Put that in for x for first equation
4(-5y+10)-5y=40
Distribute the 4
-20y+40 -5y =40
Combine like terms
-25y+40=40
Subtract 40 from both sides
-25y=0
Divide by -25 on both sides
y=0
Substitute the y in for the 2nd equation
2x+10(0)=20
2x=20
Divide both sides by 2
x=10
So x=10 and y=0
