Perhaps you meant <span>(a^3+14a^2+33a-20) / (a+4), for division by (a+4).
Do you know synthetic division? If so, that'd be a great way to accomplish this division. Assume that (a+4) is a factor of </span>a^3+14a^2+33a-20; then assume that -4 is the corresponding root of a^3+14a^2+33a-20.
Perform synth. div. If there is no remainder, then you'll know that (a+4) is a factor and will also have the quoitient.
-4 / 1 14 33 -20
___ -4_-40 28___________
1 10 -7 8
Here the remainder is not zero; it's 8. However, we now know that the quotient is 1a^2 + 10a - 7 with a remainder of 8.
9514 1404 393
Answer:
A. 2 square feet
B. draw a diagonal; 1 square foot
Step-by-step explanation:
A. The area of a parallelogram is given by the formula ...
A = bh
Here the base (b) is 3 feet, and the height (h) is 2/3 ft. The area is ...
A = (3 ft)(2/3 ft) = 2 ft^2 . . . . area of the parallelogram
__
B. <em>Drawing a diagonal</em> (AC or BD) will divide the figure into two congruent triangles. Each triangle has the same base and height as the original parallelogram. The area of one of the triangles is given by ...
A = 1/2bh
Using the given dimensions, ...
A = 1/2(3 ft)(2/3 ft) = 1 ft^2 . . . . area of one triangle
Answer: $110,400
Step-by-step explanation:
From the question, we are informed that Abby works in the sales department and this month the company is offering a 3-week paid vacation to every employee who sells 230% of the amount sold last month. We are further told that Abby sold $48,000 products last month.
To calculate the amount of product that she need to sell this month to earn the vacation, we have to multiply the amount sold last month which is $48,000 by 230%. This will be:
= $48,000 × 230%
= $48,000 × 230/100
= $48,000 × 2.3
= $110,400
Answer:
The vertices of image are A'(0,0), B'(-1,-5) and C'(4,-5). The graph of image and preimage is shown below.
Step-by-step explanation:
From the given figure it is noticed that the vertices of triangle ABC are A(0,0), B(1,5) and C(-4,5).
If a figure rotated at 180º about the origin, then
The vertices of image are
Therefore the vertices of image are A'(0,0), B'(-1,-5) and C'(4,-5).
The graph of image and preimage is shown below.
