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julia-pushkina [17]
3 years ago
6

Answer the question in the picture. (Math)

Mathematics
1 answer:
Tatiana [17]3 years ago
4 0

b has the smallest X coordinate, being 1

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Please can someone help me
disa [49]

Answer:

I believe your answer is correct.

Step-by-step explanation:

3 0
2 years ago
Select all that apply <br> thαnkѕ pєrѕσn
vodka [1.7K]
Im gonna guess and say the right ones might be
A = AB or A'B'
B = CB or C'B'
D =  CA or C'A'
Cus all equal the same side
H0P3 It H2LPS :)
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8 0
2 years ago
Factor the polynomial by it’s greatest common monomial factor. <br> 12k^3 - 30k^4
madam [21]

Answer:

6k^3(2 - 5k)

Step-by-step explanation:

12k^3 - 30k^4

Factor out 6k^3

6k^3(2 - 5k)

5 0
3 years ago
Read 2 more answers
Describe and correct the error(s) made in each of the problems below.
ladessa [460]

Answer:

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

Step-by-step explanation:

<u>Errors in Algebraic Operations </u>

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

  • When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
  • When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
  • Not to confuse product of fractions with the sum of fractions. Rules are quite different

The first expression is

1-x / (5-x)(-x)=x-1 / x(x-5)

Let's arrange into format:

\displaystyle \frac{1-x}{(5-x)(-x)} =\frac{x-1 }{ x(x-5)}

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

Now for the second expression

5/s+2/5=2/s

Let's arrange into format

\displaystyle \frac{5}{s}+\frac{2}{5} =\frac{2}{s}

It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

6 0
2 years ago
Evaluate the expression -7 1/4x + 3 5/8 for x= -4
Misha Larkins [42]

Answer:

32 5/8 (or 32 and 5/8)

Step-by-step explanation:

Okay, so this problem is asking for us to solve this problem with the substitution of a variable: x = -4. Before we fully solve this problem, we need to replace all of those x variables with -4 so that it is easier to solve.

-7 1/4(-4) + 3 5/8.

To make this problem even easier to solve, let's turn these mixed numbers into improper fractions. To do this, multiply the denominator by the whole number. Then add the numerator to this number. The new number that you just got is now your new numerator for this number.

-29/4(-4) + 3 5/8.

Repeat the last step to turn the other mixed number into an improper fraction.

-29/4(-4) + 29/8.

Now let's multiply that -4 by 29/4. Because a whole number technically has a denominator of 1, we can now set up the next part of our problem. (The symbol * means multiplication since we can't use x since it is already being used as a variable in this equation.)

(-29/4 * -4/1) + 29/8.

29 + 29/8.

Now to solve the rest of this problem, let's convert the whole number of 29 so that it has a denominator of 8. This is that these two numbers are addable.

<u>29</u> x <u>8</u> = <u>232</u>

1   x 8 =   8

Now these numbers are addable. So:

232/8 + 29/8 = 261/8 = 32 5/8.

I hope that this helps.

4 0
2 years ago
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