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3 years ago

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A metalworker has a metal alloy that is 30% copper and another alloy that is 70% copper. How many kilograms of each alloy should

the metalworker combine to create 120 kg of a 54% copper alloy?

1 answer:

neonofarm [45]3 years ago

6 0

Answer:

We will have to assume that both the 30% and 70% alloys "weigh" the same. (Have the same density.)

We'll call the 30 % copper "t" and the 70 % copper "s"

A) t + s = 120

B) .30t + .70s = .54 * 120

Multiplying equation A) by -.30 we get

A) -.30t -.30s = -36 then adding this to B)

B) .30t + .70s = 64.8 we get

.40s = 28.8

s = 72 kg and t = 48 kg

Double-Check

48 * .30 + 72 * .70 = 14.40 + 50.40 = 64.8 and

64.8 / 120 = .54 = 54 per cent

Correct!!!

Source: https://www.1728.org/mixture.htm

See Example A

Step-by-step explanation:

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Step-by-step explanation:

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Unit 7: Polygons and Quadrilaterals Homework 6: Kites Need Help Stat PLEASE HELP!!!!! 20 POINTS

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1) The measures of angles H and F are 121°, respectively.

2) The measures of angles U and V are 65° and 139°, respectively.

3) The <em>missing</em> angles are $m \angle 1 = 72^{\circ}$ , $m\angle 2 = 72^{\circ}$ , $m\angle 3 = 47^{\circ}$ , $m\angle 4 = 90^{\circ}$ , $m\angle 5 = 18^{\circ}$ , $m\angle 6 = 47^{\circ}$ and $m\angle 7 = 43^{\circ}$ .

4) The <em>missing</em> angles are $m \angle 1 = 55^{\circ}$ , $m\angle 2 = 35^{\circ}$ , $m\angle 3 = 35^{\circ}$ , $m\angle 4 = 90^{\circ}$ , $m \angle 5 = 55^{\circ}$ , $m \angle 6 = 67^{\circ}$ , $m\angle 7 = 67^{\circ}$ , $m\angle 8 = 23^{\circ}$ and $m \angle 9 = 23^{\circ}$ , respectively.

5) The measure of side $QT$ is $\sqrt{105}$ .

6) The measure of side $DF$ is $4\sqrt{26}$ .

7) The measure of side $NP$ is $3\sqrt{65}$ .

8) The value of $x$ is 17.

9) The value of $x$ is 6.

10) The measure of angle EDC is 107°.

11) The measure of angle RST is 122°.

<h3>How find missing angles and sides in rhombuses</h3>

1) According to geometry, the sum of <em>internal</em> angles in a quadrilateral equals 360°. Since the given figure is a <em>kite-type</em> rhombus, the measures of angles H and F are 121°, respectively. $\blacksquare$

2) According to geometry, the sum of <em>internal</em> angles in a quadrilateral equals 360°. Since the given figure is a <em>kite-type</em> rhombus, the measures of angles U and V are 65° and 139°, respectively. $\blacksquare$

3) According to geometry, the sum of <em>internal</em> angles in a triangle equals 180° and the sum of <em>internal</em> angles in a quadrilateral equals 360°. The <em>missing</em> angles are $m \angle 1 = 72^{\circ}$ , $m\angle 2 = 72^{\circ}$ , $m\angle 3 = 47^{\circ}$ , $m\angle 4 = 90^{\circ}$ , $m\angle 5 = 18^{\circ}$ , $m\angle 6 = 47^{\circ}$ and $m\angle 7 = 43^{\circ}$ , respectively. $\blacksquare$

4) According to geometry, the sum of <em>internal</em> angles in a triangle equals 180° and the sum of <em>internal</em> angles in a quadrilateral equals 360°. The <em>missing</em> angles are $m \angle 1 = 55^{\circ}$ , $m\angle 2 = 35^{\circ}$ , $m\angle 3 = 35^{\circ}$ , $m\angle 4 = 90^{\circ}$ , $m \angle 5 = 55^{\circ}$ , $m \angle 6 = 67^{\circ}$ , $m\angle 7 = 67^{\circ}$ , $m\angle 8 = 23^{\circ}$ and $m \angle 9 = 23^{\circ}$ , respectively. $\blacksquare$

5) In this case we need to apply Pythagorean theorem and <em>triangle</em> and <em>quadrilateral</em> properties to determine the missing side:

$QT = \sqrt{PQ^{2}-PT^{2}}$

$QT = \sqrt{13^{2}-8^{2}}$

$QT = \sqrt{105}$

The measure of side $QT$ is $\sqrt{105}$ . $\blacksquare$

6) In this case we need to apply Pythagorean theorem and <em>triangle</em> and <em>quadrilateral</em> properties to determine the missing side:

$DF = 2\cdot DH$ , $DH = \sqrt{DE^{2}-EH^{2}}$

$DF = 2\cdot \sqrt{DE^{2}-EH^{2}}$

$DF = 2\sqrt{15^{2}-11^{2}}$

$DF = 4\sqrt{26}$

The measure of side $DF$ is $4\sqrt{26}$ . $\blacksquare$

7) In this case we need to apply Pythagorean theorem and <em>triangle</em> and <em>quadrilateral</em> properties to determine the missing side:

$NK = 7\cdot x - 1$ , $NM = 10\cdot x - 13$ , $KM = 24$ , $NK = NM$ , $KP = \frac{KM}{2}$

$NP = \sqrt{NK^{2}-KP^{2}}$

$NP = \sqrt{[7\cdot (4)-1]^{2}-12^{2}}$

$NP = 3\sqrt{65}$

The measure of side $NP$ is $3\sqrt{65}$ . $\blacksquare$

8) According to geometry, the sum of <em>internal</em> angles in a quadrilateral equals 360°. Since the given figure is a <em>kite-type</em> rhombus, the value of $x$ is 17. $\blacksquare$

9) According to geometry, the sum of <em>internal</em> angles in a quadrilateral equals 360°. Since the given figure is a <em>kite-type</em> rhombus, the value of $x$ is 6. $\blacksquare$

10) According to geometry, the sum of <em>internal</em> angles in a triangle equals 180°. Hence, we have the following expressions:

$m\angle EDC = 180^{\circ}-90^{\circ}-[2\cdot (2)+13]$

$m\angle EDC = 107^{\circ}$

The measure of angle EDC is 107°. $\blacksquare$

11) According to geometry, the sum of <em>internal</em> angles in a triangle equals 180°. Hence, the angle RST is:

$m\angle RST = 2\cdot (3\cdot 12 +25)$

$m \angle RST = 122^{\circ}$

The measure of angle RST is 122°. $\blacksquare$

To learn more on quadrilaterals, we kindly invite to check this verified question: brainly.com/question/25240753

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3 years ago

Larry makes sandwiches for lunch everyday. he can make 5 sandwiches with every 3 tomatoes he buys. if he bought 9 tomatoes, how

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So if there's 9, that makes 3 groups of 3 tomatoes which would make 3x5 or 5+5+5 ;-;
15.

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3 years ago