Question

What is the equation in point -slope form. of the line passing through (0, 5) and (-2,11)

Answer 1

First, you need to find the slope of the line. You can use this with the slope formula, $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$, where the x's and y's are the given coordinates.

$\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$   Plug in the coordinates
$\frac{11 - 5}{-2 - 0}$   Subtract
$\frac{6}{-2}$   Divide
-3

Now, plug the slope (m) and one pair of coordinates, I'll use (-2, 11), into point-slope form, $y - y_{1} = m (x - x_{1})$.

$y - y_{1} = m (x - x_{1})$   Plug in the values
y - 11 = -3 (x - (-2)   Cancel out the double negative
y - 11 = -3 (x + 2)