Y=4x - x²
dy/dx = 4-2x
dy/dx | x=1 : 4-2(1) = 4-2= 2
gradient= 2
Angles ∠MOK and ∠NOL are identical by opposite angle theorem.
∠M = ∠N through given information
∠MKO and ∠NLO are congruent. Since the other two angles of each triangle are equivalent, the last angle must be equivalent to the last angle of the other triangle. (180 - ∠1 -∠2 = ∠3); you could also prove ∠MKO = ∠NLO by stating that the opposite sides of the two angles are congruent.
ΔMKO and ΔNLO by Angle-Angle-Side theorem
since ΔMKO and ΔNLO, all corresponding parts of both triangles are congruent, so therefore MO ≅ NO
Short answer: - 1
The first thing you should do is draw this or get a program to do it. I use desmos. It is included. The graph shows one complete cycle every 2*pi intervals (or 360 degrees.)
You will find no lower value that y = - 1 (nor any value greater than y = 1)