Question

6x-4y=-15 and x-4y=1

Answer 1

Answer:

The solution to the given system of equations is

($-\frac{16}{5}$,$-\frac{21}{20}$)

Step-by-step explanation:

Given system of equation are

$6x-4y=-15\hfill (1)$

$x-4y=1\hfill (2)$

To solve equation by using elimination method

Now subtracting equations (1) and (2)

$6x-4y=-15$

$x-4y=1$

_________________

5x=-16

$x=-\frac{16}{5}$

Substitute $x=-\frac{16}{5}$  in equation (1)

$6(-\frac{16}{5})-4y=-15$

$-\frac{96}{5}-4y=-15$

$-4y=-15+\frac{96}{5}$

$-4y=\frac{21}{5}$

$y=-\frac{21}{20}$

Therefore the solution is

($-\frac{16}{5}$,$-\frac{21}{20}$)