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charle [14.2K]
3 years ago
8

Find three consecutive odd integers such that the sum of the smaller two is three times the largest increased by seven

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
Let the three odd integers be x - 2, x and x + 2
x - 2 + x = 3(x + 2) + 7
2x - 2 = 3x + 6 + 7
2x - 2 = 3x + 13
3x - 2x = -2 - 13
x = -15

The three consecutive odd integers are -17, -15 and -13.
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Answer:

k=\frac{-11}{2}.

Step-by-step explanation:

We are given \alpha and \beta are zeros of the polynomial x^2-(k+6)x+2(2k-1).

We want to find the value of k if \alpha+\beta=\frac{1}{2}.

Lets use veita's formula.

By that formula we have the following equations:

\alpha+\beta=\frac{-(-(k+6))}{1}  (-b/a where the quadratic is ax^2+bx+c)

\alpha \cdot \beta=\frac{2(2k-1)}{1} (c/a)

Let's simplify those equations:

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If \alpha+\beta=k+6 and \alpha+\beta=\frac{1}{2}, then k+6=\frac{1}{2}.

Let's solve this for k:

Subtract 6 on both sides:

k=\frac{1}{2}-6

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k=\frac{1}{2}-\frac{12}{2}

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7 0
3 years ago
If a number is odd, then it has a remainder of 1 when divided by 2.
kherson [118]

Answer:

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Step-by-step explanation:

The statement can be represented by the following proposition:

P \implies Q (Eq. 1)

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Q is the conclusion of the proposition.

\implies - Binary connector, which means "If...., then...."

In this case, we present what each propostion represents:

P = A number is odd.

Q = It has a remainder of 1 when divided by 2.

In consequence, the hypothesis of the conditional is "<em>A number is odd</em>".

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