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earnstyle [38]
3 years ago
12

alpha and beta are the zeros of the polynomial x^2 -(k +6)x +2(2k -1). Find the value of k if alpha + beta = 1/2 alpha beta(ITS

URGENT)
Mathematics
1 answer:
serious [3.7K]3 years ago
7 0

Answer:

k=\frac{-11}{2}.

Step-by-step explanation:

We are given \alpha and \beta are zeros of the polynomial x^2-(k+6)x+2(2k-1).

We want to find the value of k if \alpha+\beta=\frac{1}{2}.

Lets use veita's formula.

By that formula we have the following equations:

\alpha+\beta=\frac{-(-(k+6))}{1}  (-b/a where the quadratic is ax^2+bx+c)

\alpha \cdot \beta=\frac{2(2k-1)}{1} (c/a)

Let's simplify those equations:

\alpha+\beta=k+6

\alpha \cdot \beta=4k-2

If \alpha+\beta=k+6 and \alpha+\beta=\frac{1}{2}, then k+6=\frac{1}{2}.

Let's solve this for k:

Subtract 6 on both sides:

k=\frac{1}{2}-6

Find a common denominator:

k=\frac{1}{2}-\frac{12}{2}

Simplify:

k=\frac{-11}{2}.

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