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3 years ago

Find the quadratic function y=a(x-h)^2 whose graph passes through the given points. (12,-7) and (9,0)

Mathematics

1 answer:

ryzh [129]3 years ago

6 0

Answer:

y = (-7/3)(x - 9)

Step-by-step explanation:

(12, - 7)

y = a(x - h)^2

-7 = a(12 - h)^2

- 7 = a(144 - 24x + h^2)

(9,0)

0 = a(x - h)^2

0 = a(9 - h)^2

0 = a(81 - 18h + h^2)

From (9,0) we can conclude that

a = 0

(9 - h)^2 = 0

Let's try the second possibility.

Take the square root of both sides.

9 - h = sqrt(0)

Add h to both sides

9 - h = 0

h = 9

So now what we have is

y = a(x - 9)

Use the first equation to get a

-7 = a(12 - 9)

-7 = a(3)

-7/3 = a

Answer

y = (-7/3)(x - 9)

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Answer:

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We will proceed to solve the problem in parts so that it can be better understand

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3 years ago

In ΔUVW, the measure of ∠W=90°, WV = 39, UW = 80, and VU = 89. What ratio represents the cosine of ∠U?

kumpel [21]

Answer:

cos ∅ = 80/89

Step-by-step explanation:

As required from the question the picture below represent a triangle UVW . The angle W = 90°. The sides WV = 39 , VU = 89 and UW = 80. The triangle forms a right angle triangle .

Such triangle one can establish trigonometric relationship using the SOHCAHTOA principle.

The question requested us to find the ratio that represent the cosine of ∠U.

The ∠U is represented as ∅ .

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cos ∅ = adjacent/hypotenuse

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