Step-by-step explanation:
The equation of a circle can be the expanded form of
\large \text{$(x-a)^2+(y-b)^2=r^2$}(x−a)
2
+(y−b)
2
=r
2
where rr is the radius of the circle, (a,\ b)(a, b) is the center of the circle, and (x,\ y)(x, y) is a point on the circle.
Here, the equation of the circle is,
\begin{gathered}\begin{aligned}&x^2+y^2+10x-4y-20&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4-49&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &x^2+10x+25+y^2-4y+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &(x+5)^2+(y-2)^2&=&\ \ 7^2\end{aligned}\end{gathered}
⟹
⟹
⟹
⟹
x
2
+y
2
+10x−4y−20
x
2
+y
2
+10x−4y+25+4−49
x
2
+y
2
+10x−4y+25+4
x
2
+10x+25+y
2
−4y+4
(x+5)
2
+(y−2)
2
=
=
=
=
=
0
0
49
49
7
2
From this, we get two things:
\begin{gathered}\begin{aligned}1.&\ \ \textsf{Center of the circle is $(-5,\ 2)$.}\\ \\ 2.&\ \ \textsf{Radius of the circle is $\bold{7}$ units. }\end{aligned}\end{gathered}
1.
2.
Center of the circle is (−5, 2).
Radius of the circle is 7 units.
Hence the radius is 7 units.
Answer:
60°
Step-by-step explanation:
Am equilateral triangle is a triangle that has all its sides and angles equal. Note that an equilateral triangle has 3 sides and angles.
Let the angles be a, b and c
The sum of angle in a triangle is 180°, hence;
a+b+c = 180°
Since a = b = c
The equation becomes;
a+a+a = 180°
3a = 180
a = 180/3
a = 60°
Hence the measure of the angles of an equilateral triangle is 60° for the three angles.
Answer:
E: L is perpendicular to a line with slope 
.
Lines are perpendicular if the negative reciprocal of the slope is equal. For example, the reciprocal of 
is 
(remember, to get the reciprocal, simply switch the numerator and the denominator).
So, the negative reciprocal of is . This represents the slope of a line that is perpendicular.
Bonjour!
For A, the two angles are congruent by the Corresponding Angles are Congruent Theorem/Postulate.
For B, the two angles are congruent by the Vertical Angels are Congruent Theorem/Postulate.
As for C, the two angles are congruent by the Same Side Exterior Theorem/Postulate.(Though I am uncertain if that is the correct name for this one)
Hope that helps :)
