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3 years ago

Choose the fraction that has not been reduced to simplest form.

Mathematics

2 answers:

EleoNora [17]3 years ago

7 0

The answer would be (C).

To be fully simplified, the numerator and denominator must have a GCF of 1.

Answer (C) says 3/57. However, using the divisibility rule of 3 (add the digits together, and if the sum is a multiple of 3, then the number is as well), we see that 57 is divisible by 3, meaning this fraction is not simplified. The simplified version would be 1/19.

Bingel [31]3 years ago

7 0

When a fraction is in reduced form, one of the numbers will be a multiple of the other.

In $\frac{11}{17}$ one of the numbers is NOT a multiple of the other.

In $\frac{5}{16}$ one of the numbers is NOT a multiple of the other.

In $\frac{3}{57}$ one of the numbers IS a multiple of the other.

$\frac{3 \div 3}{57 \div 3} = \frac{1}{19}$

In $\frac{21}{34}$ one of the numbers is NOT a multiple of the other.

Your answer is C

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Find the value of x

Ivahew [28]

Answer:

x=27

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

90 + x+23 + x+13 = 180

Combine like terms

126 +2x = 180

Subtract 126 from each side

126-126 +2x=180-126

2x =54

Divide by 2

2x/2 = 54/2

x = 27

4 0

3 years ago

Patrick works a 40-hour week at $10.70 an hour with time and a half for overtime. Last week he worked 45 hours. What were his to

vredina [299]

its 454.75$ either the answers you are wrong or idk

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3 years ago

Suppose the scores on a test given to all juniors in a school district are normally distributed with a mean of 74 and a standard

ivann1987 [24]

Answer:

$\mu -\sigma = 66 , \mu +\sigma = 82$

$\mu -2\sigma = 58 , \mu +2\sigma = 90$

$\mu -3\sigma = 50 , \mu +3\sigma = 98$

And in the figure attached we see the limits with the percentages associated.

Step-by-step explanation:

For this case we know that the random variable of interest is the scores on a test given to all juniors in a school district follows a normal distribution with the following parameters:

$X \sim N(\mu= 74, \sigma =8)$

For this case we know from the empirical rule that within one deviation from the mean we have approximately 68.2% of the data, within 2 deviations from the mean we have 95% and within 3 deviation 99.7%

We can find the limits and we got:

$\mu -\sigma = 66 , \mu +\sigma = 82$

$\mu -2\sigma = 58 , \mu +2\sigma = 90$

$\mu -3\sigma = 50 , \mu +3\sigma = 98$

And in the figure attached we see the limits with the percentages associated.

7 0

4 years ago

Using these complex zeros (1,1,-1/2,2+i,2-i) factor f(x)=-2x^5 +11x^4 -22x^3 +14x^2 +4x -5

Marianna [84]

$\bf \begin{cases}
x=1\implies &x-1=0\\
x=1\implies &x-1=0\\
x=-\frac{1}{2}\implies 2x=-1\implies &2x+1=0\\
x=2+i\implies &x-2-i=0\\
x=2-i\implies &x-2+i=0
\end{cases}
\\\\\\
(x-1)(x-1)(2x+1)(x-2-i)(x-2+i)=\stackrel{original~polynomial}{0}
\\\\\\
(x-1)^2(2x+1)~\stackrel{\textit{difference of squares}}{[(x-2)-(i)][(x-2)+(i)]}$

$\bf (x^2-2x+1)(2x+1)~[(x-2)^2-(i)^2]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)-(-1)]
\\\\\\
(x^2-2x+1)(2x+1)~[(x^2-4x+4)+1]
\\\\\\
(x^2-2x+1)(2x+1)~[x^2-4x+5]
\\\\\\
(x^2-2x+1)(2x+1)(x^2-4x+5)$

of course, you can always use (x-1)(x-1)(2x+1)(x²-4x+5) as well.

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3 years ago

Can someone please help me with these 2 questions

soldi70 [24.7K]

Number 8 would be B. Number 9 would be A. Hope this helps! Mark brainliest? :))

3 0

3 years ago

Read 2 more answers