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2 years ago

Write an inequality that compares-6, 3, and 5

Mathematics

1 answer:

olga_2 [115]2 years ago

8 0

Is that 6 or negative 6? I'll do both situations, as I can't tell (sorry!)

With negative 6:

-6 < 3 < 5

With positive 6:

3 < 5 < 6

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What is workers compensation?

Natali [406]

Insurance providing salary to employees injured while working.

6 0

2 years ago

The inverse, f'(x), of f(x) =

astraxan [27]

Step-by-step explanation:

Given

$f(x) = \frac{x + 5}{x}$

$f(2) = \frac{2 + 5}{2} \\ = \frac{7}{2}$

Now

${f}^{ - 1} (x) = \frac{5}{x - 1}$

${f}^{ - 1} (2) = \frac{5}{2 - 1} \\ = \frac{5}{ 1} \\ = 5$

Hope it will help :)❤

7 0

1 year ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$

The standard deviation of a sample of n young man is given by the following formula

$s = \frac{\sigma}{\sqrt{n}}$

We want to have $s = 0.167$

$0.167 = \frac{2.8}{\sqrt{n}}$

$0.167\sqrt{n} = 2.8$

$\sqrt{n} = \frac{2.8}{0.167}$

$\sqrt{n} = 16.77$

$\sqrt{n}^{2} = 16.77^{2}$

$n = 281.23$

We need a sample of at least 282 young men.

6 0

2 years ago

Witch multiples of 24 are not factors of 24

Nataly [62]

Answer:

A factor of 24 is a number that can be multilied by another number (normally whole (not fraction or decimal) numbers) so a factor must be less than the number any multiple of 2 greater than 24 will work so just any even number greater than 24 exg 26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60, and so on.

Step-by-step explanation:

8 0

2 years ago

A 24-foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground 6 feet

andrezito [222]

Answer:

23.24 feet

Step-by-step explanation:

Use the pythagorean theorem: a² + b² = c², where a and b are legs of the right triangle and c is the hypotenuse.

In this situation, the ladder is the hypotenuse of the triangle, and the distance from the base of the building is the long leg.

Plug in the ladder length as c and plug in the distance from the base of the building as a:

a² + b² = c²

(6²) + b² = (24)²

36 + b² = 576

b² = 540

b = 23.24

So, the ladder reaches approximately 23.24 feet up the wall

5 0

2 years ago

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