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PSYCHO15rus [73]
3 years ago
11

Write an inequality that compares-6, 3, and 5

Mathematics
1 answer:
olga_2 [115]3 years ago
8 0

Is that 6 or negative 6? I'll do both situations, as I can't tell (sorry!)

With negative 6:

-6 < 3 < 5

With positive 6:

3 < 5 < 6

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Which relation is a function?
tresset_1 [31]

Answer: It is the top right one.

Step-by-step explanation: That one passes the vertical line test. A function can't have any points that have the same x-coordinate.

7 0
3 years ago
What is 1+17+13+23+35+12+12+35+34
Sunny_sXe [5.5K]
The answer is 182, i hope this helps!

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6 0
3 years ago
Initially, there were only 86 weeds in the garden. The weeds grew at a rate of 29% each week. The following function represents
Orlov [11]

Step-by-step answer:

The base of the exponential function is 1.29 for 7 days, as in

f(x) = 86*(1.29)^x

The new rate for days can be calculated by dividing x by 7 (where x remains the number of weeks), namely

f(x) = 86*1.29^(x/7)

Using the law of exponents, b^(x/a) = b^(x*(1/a)) = (b^(1/a))^x

we simplify by putting b=1.29, a=7 to get

f(x) = 86*(1.29^(1/7))^x

f(x) = 86*(1.037)^x      since 1.29^(1/7) evaluates to 1.037

Rounding 1.037 to 1.04 we get a (VERY) approximate function

f(x) = 86 * (1.04^x)

1.04 is very approximate because 1.04^7 is supposed to get back 1.29, but it is actually 1.316, while 1.037^7 gives 1.2896, much closer to 1.29.

7 0
3 years ago
Read 2 more answers
I need help with this plz help
Nataly_w [17]

Answer:

just swap the first two and you should be good

5 0
3 years ago
Quiz scores of statistics students were obtained by a teacher and listed below. Construct a frequency distribution beginning wit
DanielleElmas [232]

Answer:

The frequency distribution is

The frequency distribution is

S/N Class limit Frequency

1 0-2 4

2 3 -4 1

3 5-6 2

4 7-8 2

5 9 - 10 0

6 11 - 12 0

The value for value upper class boundary of the fifth class is CB_5 =  10.5

Step-by-step explanation:

From the question we are told that

The lower class limit is 0

The class width is 2

The scores is 8,6,2,4,2,0,2,6,7

The frequency distribution is

S/N Class limit Frequency

1 0-2 4

2 3 -4 1

3 5-6 2

4 7-8 2

5 9 - 10 0

6 11 - 12 0

Generally the upper class boundary of the fifth class is mathematically represented as

CB_5 =  \frac{10 + 11}{2}

            CB_5 =  10.5

8 0
3 years ago
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