2 years ago

Help me with question number 3 please!!!

Mathematics

1 answer:

grin007 [14]2 years ago

5 0

Answer: please mark brainlyest

Step-by-step explanation:

You might be interested in

What is the distance between points (6,2) and (4,1) to the nearest tenth?

RoseWind [281]

Approximately 7.2 units <span />

5 0

3 years ago

The new e-reader measures 8 inches long, 5 inches wide, and 2 inches deep. which is the correct unit of measurement to use when

Diano4ka-milaya [45]

Inches cubed. Or inches^3

4 0

3 years ago

Read 2 more answers

Write an absolute value inequality for each of the following. Then graph the

n200080 [17]

An absolute value inequality for "all numbers less than 7 and greater than -7" is given by |x| < 7.

<h3>How to write an absolute value inequality?</h3>

Based on the information provided, we can logically deduce that the statement describes an intersection of set because the word "and" was used.

This ultimately implies that, we would use the less than (<) symbol to write an absolute value inequality for the given statement:

|x| < 7

Therefore, this can be translated as follows:

-7 < x < 7 or x < 7 and x > -7.

Read more on number line here: brainly.com/question/24644930

#SPJ1

8 0

2 years ago

Find the probability that a randomly-chosen ninth grader will be absent 2 days next month.

miss Akunina [59]

Answer:

90% chance that it could happen.

7 0

3 years ago

given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta

lapo4ka [179]

Answer:

$\cos{\theta} = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

For any angle $\theta$ , we have that:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

Quadrant:

$0 \leq \theta \leq \frac{\pi}{2}$ means that $\theta$ is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

$(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1$

$\frac{1}{16} + (\cos{\theta})^{2} = 1$

$(\cos{\theta})^{2} = 1 - \frac{1}{16}$

$(\cos{\theta})^{2} = \frac{16-1}{16}$

$(\cos{\theta})^{2} = \frac{15}{16}$

$\cos{\theta} = \pm \sqrt{\frac{15}{16}}$

Since the angle is in the first quadrant, the cosine is positive.

$\cos{\theta} = \frac{\sqrt{15}}{4}$

3 0

3 years ago