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andreyandreev [35.5K]
3 years ago
14

Trapezoid TUVW is shown on the coordinate plane below: Trapezoid TUVW on the coordinate plane with ordered pairs at T negative 4

, negative 1, at U negative 1, negative 1, at V negative 1, negative 4, at W negative 6, negative 4. If trapezoid T'U'V'W' represents trapezoid TUVW reflected over the y-axis, the ordered pair of W' is ___________. (Note: You must include parentheses, a comma, and a space after the comma when typing the ordered pair.)
Mathematics
2 answers:
Dvinal [7]3 years ago
7 0

Answer:

The ordered pair of W' are after the reflection of the trapezoid TUVW over the y-axis are:

(6,-4)

Step-by-step explanation:

Trapezoid TUVW on the coordinate plane with ordered pairs at :

T(-4,-1) , U(-1,-1)  , V(-1,-4) , W(-6,-4)

Now trapezoid T'U'V'W' represents trapezoid TUVW reflected over the y-axis.

We know that if any figure is reflected over the y-axis then the coordinate changes is given by:

(x,y) → (-x,y)

Here T → T'

        U → U'

        V →  V'

        W → W'

Hence, the coordinates of:

T' are: (4,-1)

U' are: (1,-1)

V' are: (1,-4)

W' are: (6,-4)

Hence the ordered pair of W' are: (6,-4)

MissTica3 years ago
4 0
To reflect over the y axis, the formula is (-x, y). For W, which currently is (-6, -4), the -6 becomes -(-6), which is the same as 6, so the answer is (6, -4).
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Read 2 more answers
Reasoning Graph the set of ordered pairs (0, 2). (1.4), (2,6). (3.8). Determine whether the relationship is a linear function Ex
polet [3.4K]

Answer:

No, it does not. See below.

Step-by-step explanation:

Lets find out the linear equation that passes trough (-2, 0) and (0, -6).

We know every linear equation has the form: y = mx + b

Where m is the slope on the curve and b the independent term.

We know that, given 2 points (x1,y1) and (x2,y2) we can find the slope m as:

m = (y2-y1)/(x2-x1)

In our case lets replace (x1,y1) and (x2,y2) by (-2, 0) and (0, -6) (notice it could be done in the inverse sense where (-2, 0) is (x2,y2) and (0, -6) is (x1,y1) ). So, our slope is:

m = [-6 - 0] / [0 - (-2)]

m = -6/2 = -3

So, we have a downward linear function with slope -3, this is:

y =  -3x + b

Now, for finding b just replace any of the 2 points given in the equation. Lets replace (-2, 0):

0 = -3(-2) + b

0 = 6 + b

Subtracting 6 in both sides:

-6 = b

So, our independent term is -6 and the function is:

y = -3x - 6

Now lets see if this linear eqution passes trough (2,6). If it does, we can replace the values on the equation. Replacing x by 2:

y = -3(2) - 6 = = -6 - 6 = - 12

So, in our equation, we x is 2 y is -12, and not 6 as in the point (2,6). So, our equation does not passes trough (2,6)

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2 years ago
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