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Sav [38]
4 years ago
13

Define negative numbers

Mathematics
1 answer:
shepuryov [24]4 years ago
4 0
A negative number is a number that is below one for example if you subtract 6-7 it would equal negative 1 or -1
You might be interested in
Write 5 equations where the difference is equal to 3
mafiozo [28]
1) 4*3 - 9
2) 15 - 12
3) 4 - 1
4) 54 + 1 - 52
5) 9*3+2-26

Hope this helps!
7 0
3 years ago
Read 2 more answers
1.
creativ13 [48]

If the diameter is 12 inches, the radius is 6 inches, because the radius is half the diameter.

Given the formula

A=\pi r^2

we have

A=36\pi

When you fold the circle in half, the resulting figure has half the area.

So, you start with a circle with area 36\pi

You fold it once and you have a semicircle with area 18\pi

You fold it twice and you have a quarter circle with area 9\pi

7 0
3 years ago
Find the value of b to the power of 2, minus 4ac when a = -2, b = 5 and c = -1. Show your work.
aev [14]
The answer is 17 the work is in the photo below

6 0
3 years ago
Read 2 more answers
Help me please and thanks​
vazorg [7]

Answer:

414\pi

Step-by-step explanation:

The formula for the surface area of a cylinder is 2\pi r h + 2\pi r^2 =2\cdot \pi \cdot 9 \cdot 14 + 2\cdot \pi \cdot 9^2=252\pi + 162\pi=414\pi square inches. Hope this helps!

8 0
4 years ago
Check thepic plzz first answer brainliest
aleksandr82 [10.1K]

Answer:

Total Surface Area:  A = 88 square cm

Step-by-step explanation:

Volume V = 48 cubic cm

So this cuboidal box is actually a rectangular prism.

V =  L * W* H

L = length,   W = breadth,   H= height

With  L: W : H = 3: 2: 1

L:W = 3: 2

W: H = 2: 1

L/W  = 3/2,    L = (3/2)*W

W/H = 2/1 ,    W = 2*H

L = (3/2)*(2H) =  3H

So  :   V = L * W * H =  (3H) * (2H) * H  = 6 * H^3

48  =  6 * H^3

48/6 = 8 = H^3

H = cube-root(8) =  2 cm

so  ...

W = 2*H = 2*2 = 4 cm

L = (3/2)*W = (3/2)* 4 = 6 cm

Total Surface Area:  A = 2*LW  + 2*LH + 2*WH

A = 2*(6 * 4)  +  2*(6 * 2)  + 2*(4 * 2)

A = 2*24  + 2*12 + 2*8

A = 48 + 24 + 16

A = 48 + 40

A = 88 square cm

4 0
4 years ago
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