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gayaneshka [121]
3 years ago
5

What is the general form of the equation 2x + 3y = 9?

Mathematics
1 answer:
Olenka [21]3 years ago
6 0

Answer:

2x + 3y - 9 = 0

Step-by-step explanation:

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Can someone please help me?(Fill in the blanks) This is on Khan Academy too, I need it ASAP! if you answer right I'll mark you B
Travka [436]

First divide both sides by 2:

2x^2+7x+6=0\implies x^2+\dfrac72x+3=0

Move the constant term to the right side:

x^2+\dfrac72x=-3

Since

(x+y)^2=x^2+2xy+y^2

we want to have

2y=\dfrac72\implies y=\dfrac74

Then

\left(x+\dfrac74\right)^2=x^2+\dfrac72x+\dfrac{49}{16}

So in our equation, we need to add 49/16 to both sides in order to complete the square:

x^2+\dfrac72x+\dfrac{49}{16}=-3+\dfrac{49}{16}

\implies\left(x+\dfrac74\right)^2=\dfrac1{16}

7 0
3 years ago
What is the best estimate for the mass of a textbook, 1 gram or 1 kilogram
Delicious77 [7]
The best estimate would be one kilogram since one gram is about the mass of a paperclip.
7 0
3 years ago
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20 points, find the value of x <br><br> 7x – 2(x + 12) = -5 – 2 (1 - 3x)
frozen [14]

Answer:

read explanation

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

x = −17

5 0
3 years ago
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Points P, Q and R are collinear such that PQ : QR=2:3 point P is located at (1,3) and point R is located at (11,15)
balandron [24]

Using line segments, it is found that:

  • The coordinates of Q are (5,7.8).
  • The midpoint of segment PQ is M(6,9).

----------------------------

  • Point P is located at (1,3).
  • Point R is located at (11,15).
  • Point Q is located at (x,y).
  • PQ:QR = 2:3, which means that:

Q - P = \frac{2}{5}(R - P)

This is used to find the x and y coordinates of Q.

----------------------------

  • The <em>x-coordinate</em> of P is 1.
  • The <em>x-coordinate</em> of R is 11.
  • The <em>x-coordinate </em>of Q is x.

Thus:

Q - P = \frac{2}{5}(R - P)

x - 1 = \frac{2}{5}(11 - 1)

x - 1 = \frac{2}{5}10

x - 1 = 4

x = 5

----------------------------

  • The y<em>-coordinate</em> of P is 3.
  • The y<em>-coordinate</em> of R is 15.
  • The y<em>-coordinate </em>of Q is y.

Thus:

Q - P = \frac{2}{5}(R - P)

y - 3 = \frac{2}{5}(15 - 3)

y - 3 = \frac{24}{5}

y - 3 = 4.8

y = 7.8

The coordinates of Q are (5,7.8).

----------------------------

  • The midpoint of segment PQ is the mean of the coordinates, thus:

M = (\frac{1 + 11}{2}, \frac{3 + 15}{2}) = (\frac{12}{2}, \frac{18}{2}) = (6,9)

The midpoint of segment PQ is M(6,9).

A similar problem is given at brainly.com/question/24148182

4 0
3 years ago
The lines shown below are parallel. If the green line has a slope of -4, what is the slope of the red line?
klasskru [66]
Parallel lines will have the same slope.
So if the green line has a slope of -4, then the red line also has a slope of -4
6 0
3 years ago
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