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3 years ago

What is the general form of the equation 2x + 3y = 9?

Mathematics

1 answer:

Olenka [21]3 years ago

6 0

Answer:

2x + 3y - 9 = 0

Step-by-step explanation:

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Can someone please help me?(Fill in the blanks) This is on Khan Academy too, I need it ASAP! if you answer right I'll mark you B

Travka [436]

First divide both sides by 2:

$2x^2+7x+6=0\implies x^2+\dfrac72x+3=0$

Move the constant term to the right side:

$x^2+\dfrac72x=-3$

Since

$(x+y)^2=x^2+2xy+y^2$

we want to have

$2y=\dfrac72\implies y=\dfrac74$

Then

$\left(x+\dfrac74\right)^2=x^2+\dfrac72x+\dfrac{49}{16}$

So in our equation, we need to add 49/16 to both sides in order to complete the square:

$x^2+\dfrac72x+\dfrac{49}{16}=-3+\dfrac{49}{16}$

$\implies\left(x+\dfrac74\right)^2=\dfrac1{16}$

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3 years ago

What is the best estimate for the mass of a textbook, 1 gram or 1 kilogram

Delicious77 [7]

The best estimate would be one kilogram since one gram is about the mass of a paperclip.

7 0

3 years ago

Read 2 more answers

20 points, find the value of x 7x – 2(x + 12) = -5 – 2 (1 - 3x)

frozen [14]

Answer:

read explanation

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

x = −17

5 0

3 years ago

Read 2 more answers

Points P, Q and R are collinear such that PQ : QR=2:3 point P is located at (1,3) and point R is located at (11,15)

balandron [24]

Using line segments, it is found that:

The coordinates of Q are (5,7.8).

The midpoint of segment PQ is M(6,9).

----------------------------

Point P is located at (1,3).
Point R is located at (11,15).
Point Q is located at (x,y).
PQ:QR = 2:3, which means that:

$Q - P = \frac{2}{5}(R - P)$

This is used to find the x and y coordinates of Q.

----------------------------

The x-coordinate of P is 1.
The x-coordinate of R is 11.
The x-coordinate of Q is x.

Thus:

$Q - P = \frac{2}{5}(R - P)$

$x - 1 = \frac{2}{5}(11 - 1)$

$x - 1 = \frac{2}{5}10$

$x - 1 = 4$

$x = 5$

----------------------------

The y-coordinate of P is 3.
The y-coordinate of R is 15.
The y-coordinate of Q is y.

Thus:

$Q - P = \frac{2}{5}(R - P)$

$y - 3 = \frac{2}{5}(15 - 3)$

$y - 3 = \frac{24}{5}$

$y - 3 = 4.8$

$y = 7.8$

The coordinates of Q are (5,7.8).

----------------------------

The midpoint of segment PQ is the mean of the coordinates, thus:

$M = (\frac{1 + 11}{2}, \frac{3 + 15}{2}) = (\frac{12}{2}, \frac{18}{2}) = (6,9)$

The midpoint of segment PQ is M(6,9).

A similar problem is given at brainly.com/question/24148182

4 0

3 years ago

The lines shown below are parallel. If the green line has a slope of -4, what is the slope of the red line?

klasskru [66]

Parallel lines will have the same slope.
So if the green line has a slope of -4, then the red line also has a slope of -4

6 0

3 years ago