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2 years ago

Use inverse operations to solve: x + 3.2 = 7

Mathematics

1 answer:

Contact [7]2 years ago

6 0

Answer:

x=3.8

Step-by-step explanation:

You would use the inverse operation by subtracting 3.2 from both sides of the equation, leaving you with x=3.8

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The data in the line plot show how many pages each student read last night. Which is the best measure of variability?

AVprozaik [17]

Answer: D range
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2 years ago

Hal is asked to write an exponential function to represent the value of a $10,000 investment decreasing at 2% annually. What mul

Inga [223]

Answer

The multiplicative rate of change that should be in Hal’s function = 49/50=0.98

=9.8×10⁻¹

Explanation

The investment of $10,000 decreases by 2% every year. So the following year is usually (100 - 2)=98% of the previous year. This is a geometric progression.

In this case the first term = 10000

The second term = 98% × 10000 = 9800.

The common ratio = 9800/10000=49/50

The multiplicative rate of change that should be in Hal’s function = 49/50=0.98.

The equation of the exponential rate would be;

10,000ₓ0.98ⁿ.

where n is the number years.

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3 years ago

Which ordered pair is a solution of the equation y=4x+9

Maru [420]

What are the ordered pairs

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3 years ago

What is this answer I don't understand how to figure it out

Diano4ka-milaya [45]

These are congruent angles. So they would be equal to each other. 6x=4x+50

2x=50

x=25°
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8 0

3 years ago

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Vavilen inflated a huge balloon in 19 minutes. Then he poked a hole in the balloon so that it slowly leaked air out until it was

kaheart [24]

Considering balloon to be an spherical object

Volume of sphere = $\frac{4}{3}\pi r^3$ , where r is the radius of sphere.

After 19 minutes ,If radius of balloon changes from r to R, the Volume changes from V to V'.

V'= $\frac{4}{3}\pi R^3$ ,

As given,rate at which the air leaked out of the balloon (in liters of air per minute) was half of the rate at which Vavilen inflated the balloon.

Also, $\frac{dR}{dt}=2 \times \frac{dr}{dt}$

Now, again the radius changes from R to r.So, Volume changes from V' to Back to V.

Time taken by the balloon to deflate = 38 minutes

But there is no relation between time and volume of Balloon.

So, we can't predict at which rate balloon is deflating or inflating.Apart from the statement given in Question: $\frac{dR}{dt}=2 \times \frac{dr}{dt}$

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3 years ago

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